For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
where
A = total amount in the account at the end of t years
r represents the interest rate
n represents the periodic interval at which it was compounded
p represents the principal or initial amount deposited
From the information given,
P = 11260
t = 6
r = 7.5/100 = 0.075
n = 52(Assuming the number of weeks in a year is 52 and it would be compounded 52 times in a year)
Thus, we have
A = 11260(1 + 0.075/52)^52*6
A = 11260(1 + 0.075/52)^312
A = 17653.5
Answer:
c
Step-by-step explanation:
Answer:
(4,0)
Step-by-step explanation:
It is a linear function so you find the slope by doing y2-y1/x2-x1 and you find the slope to be 1/2. You can then setup an equation using it and graph it to find the next value.