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Fittoniya [83]
3 years ago
14

The perimeter of an isosceles triangle is 84 inches. Each of the congruent sides of the isosceles triangle is 9 inches less than

the length of its base. Write and solve an equation to find the lengths of all three sides of the triangle. Which of the following answers below represent the sum of the two congruent sides?
Mathematics
1 answer:
ohaa [14]3 years ago
7 0
K
K kkkkkkk king woman watching woo palace park so
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Tanya needs to buy chocolate bars for all the children in year 7. Each of the 130 children get one chocolate bar. There are 8 ch
Sedaia [141]

Answer:

17 packets

Step-by-step explanation:

So Tanya needs 130 chocolate bars.

But there is 8 in each packet.

So,

130 ÷ 8 = 16.25

16 packets

As you can see, there is a quarter left of chocolates that she needs (0.25). So what she can do is buy 1 more packet then give the quarter of that packet to the children.

So 16 + 1 = 17 packets

4 0
3 years ago
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(555.28-122.57*(4))-(585.34-136.71*(4))
mamaluj [8]
26.5 ..................................

7 0
3 years ago
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8−i
GalinKa [24]

Hi Veracity,

Answer:

(2 + i) = 2

Step-by-step explanation:

Multiply the denominator and numerator by the conjugate,

= \frac{(8 - i)(3 + 2i)}{13}

Combine Like Terms,

= \frac{26 + 13i}{13}

Simplify,

= 2 + i

Hope This Helps :)

3 0
2 years ago
Mrs Lim bought a number of plates at an average price of $6. She decided to buy another plate which cost $18. The average price
soldi70 [24.7K]

Answer:  6

<u>Step-by-step explanation:</u>

Let x represent the number of plates bought for $6

Let y represent the Total number of plates bought = x + 1

<em>Remember that Mrs. Lim bought another plate for $18</em>

Total cost ÷ Total plates = Average Cost

\dfrac{6x+18}{x+1}=8\\

6x + 18 = 8(x + 1)

6x + 18 = 8x + 8

       18 = 2x + 8

       10 = 2x

        5 = x

y = x + 1

  = 5 + 1

  = 6

5 0
3 years ago
WILL MARK YOU BRAINLIEST HURRY!
wel

Answer:

its  n II m

Step-by-step explanation:

Its one of the things I remember from geometry XD

3 0
3 years ago
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