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2 years ago

SOMEONE PLEASE HELP ME ASAP THIS IS ALMOST DUE ILL MARK BRAINLIEST!!!!

Mathematics

1 answer:

makkiz [27]2 years ago

3 0

Answer:

153

Step-by-step explanation:

If the table adds up to 20 and opened toe counts for 45% of the total. then 45% of 340 is 153 !

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An automobile maker has an order for 7,500 new cars to be delivered in one week. Each car must be fitted with a new hood ornamen

babymother [125]

Time to fit 7500 cars = 7500 * 1.25 hoursnumber of hours available in week = 40 hoursnumber of workers needed = 7500* 1.25 / 40 = 234.4number required = 235

5 0

2 years ago

Read 2 more answers

The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is

Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = average gestation period = 270 days

$\sigma$ = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X $\leq$ 261)

P(X < 279) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{279-270}{9}$ ) = P(Z < 1) = 0.84134

P(X $\leq$ 261) = P( $\frac{ X - \mu}{\sigma}$ $\leq$ $\frac{261-270}{9}$ ) = P(Z $\leq$ -1) = 1 - P(Z < 1)

= 1 - 0.84134 = 0.15866

Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0

3 years ago

PLEASE HELPPPPPPPPPP

Sauron [17]

Answer:

167/346 or 0.483

Step-by-step explanation:

From the question given above, the following data were obtained:

Number of Tails (T) = 167

Number of Heads (H) = 179

Probability of tail, P(T) =?

Next, we shall determine total outcome. This can be obtained as follow:

Number of Tails (T) = 167

Number of Heads (H) = 179

Total outcome (S) =?

S = T + H

S = 167 + 179

Total outcome (S) = 346

Finally, we shall determine the probability of tails. This can be obtained as follow:

Number of Tails (T) = 167

Total outcome (S) = 346

Probability of tail, P(T) =?

P(T) = T / S

P(T) = 167 / 346

P(T) = 0.483

Thus, the probability of tails is 167/346 or 0.483

3 0

2 years ago

Any body know the answers to these

snow_lady [41]

For 3. he answer is a
for 4 the answer is two

6 0

3 years ago

The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand

alexira [117]

Answer:

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

t = 1.076

Step-by-step explanation:

Step(i):-

Given Mean of the Population (μ) = 8.0

Mean of the sample (x⁻) = 8.25

Given data

8,9,9,8,8,9,8,7

Given sample size n= 8

Given sample standard deviation(S) = 0.661

Step(ii):-

Null hypothesis : H: (μ) = 8.0

Alternative Hypothesis :H:(μ) > 8.0

Degrees of freedom = n-1 = 8-1=7

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }$

t = 1.076

Critical value

t₍₇,₀.₀₅₎ = 2.3646

The calculated value t = 1.076 < 2.3646 at 0.05 level of significance

Null hypothesis is accepted

Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0

3 0

2 years ago