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VARVARA [1.3K]
3 years ago
9

Find dy/dx of y=csc(square root of x)

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer:

y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}

Step-by-step explanation:

y = csc x

y' = -cot x csc x

y = \csc \sqrt{x}

y' = \dfrac{d}{dx} [\csc \sqrt{x}]

y' = (-\cot x \csc x) \dfrac{d}{dx} \sqrt{x}

y' = (-\cot x \csc x) \dfrac{d}{dx} x^{\frac{1}{2}}

y' = (-\cot x \csc x) \dfrac{1}{2} x^{-\frac{1}{2}}

y' = -\dfrac{\cot x \csc x}{2 \sqrt{x}}

You might be interested in
12.6% of<br>RI 149 390bn​
galina1969 [7]

Answer: RI 18,823.14

Step-by-step explanation:

I guess that we want to find the 12.6% of Rl 149,390

First, we assume that Rl 149,390 is the 100%

Then we can write an equation like:

Rl 149,390 = 100%

Then if the amount X is the 12.6%, we also have the equation:

X = 12.6%

Then we have the two equations:

X = 12.6%

Rl 149,390 = 100%

If we take the quotient between these two equations we get:

(X/Rl 149,390) = (12.6%/100%)

Solving this for X we get:

X =  (12.6%/100%)*(Rl 149,390) = RI 18,823.14

7 0
3 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
3 years ago
Which of the following numbers can be expressed as repeating decimals? 3 over 7, 2 over 5, 3 over 4, 2 over 9
Maurinko [17]

Hello!

Let's think about the denominators we have. A seventh goes on forever in no specified order. A fifth an a fourth have set decimal values, 0.2 and 0.25, so they are not repeating decimals. A ninth is 0.111111..., it repeats like this forever in a specified order. Therefore, 2/9, or 0.222222...., would be a repeating decimal.

Therefore, our answer is \boxed {\frac{2}{9}}.

I hope this helps!

6 0
3 years ago
The area of a square is given by x2, where x is the length of one side. Mary's original garden was in the shape of a square. She
Viefleur [7K]

2( {x}^{2} )

3 0
3 years ago
Determine the solution set of each equation
maks197457 [2]

A=x1 = -8,x2 =2, B=x1= -5,x2=5, C=y1 = -4, y2 =5, D=y 18 over 5

alternative form

y=3 3over 5, =3.6

And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

x2 +8x-2x-16=0

factor out x for the expression

xx(x+8)-2x-16=0

factor out -2 from the expression

xx(x+8)- 2(x+8)=0

factor out x+8 from the expression

(x+8)x(x- 2)=0

when the product of factors equals 0,at least one factor is 0

x+8=0

x - 2=0

solve the equation for x

x= -8

x - 2=0

solve the equation for x

x= -8

x =2

the equation has 2 solution

x1 = -8,X2 =2

answer is

x1 = -8,x2 =2

Or

Solving steps:Number of solution

x²+6x-16=0

Determine the number of solution using the

discriminant D =b²- 4ac

D =6²- 4x1x(-16)

simply the expression

D=100

Since D>0, the quadratic equation has 2 real solution

2 real solution

Answer is

2 real solution

Question B

Solving steps:Solve the quadratic equation

x²-25=0

Move the constant to the right-hand side and change its sign

x²=25

Take the square root of both sides of the equation and remember to use both positive and negative roots

x=+5

Write the solutions,one with a +sign and one with a -sign

x= -5

x=5

The equation has 2 solutions

x1= -5,x2=5

the answer is

x1= -5,x2=5

Or

Solving steps:Number of solution

x²-25=0

Determine the number of solutions using the discriminant D=b²- 4ac

D=0²- 4x1x(-25)

Simply the expression

D=100

Since D>0,the quadratic equation has 2real solutions

Answer is

2real solutions

answer of question C is

y1 = -4, y2 =5

Answer of question D is

y 18 over 5

alternative form

y=3 3over 5, =3.6

Answer of question E is

x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667

Please mark as brainiest

3 0
3 years ago
Read 2 more answers
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