1 year ago

What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)

Mathematics

1 answer:

maxonik [38]1 year ago

4 0

Let f(x) = x² + 6x²-x+ 5 then ,

number to be added be P

then,

f(x) = x² + 6x²-x+ 5 +P

According to the qn,

(x+3) is exactly divisible by zero then,

R=0

comparing .. we get a= -3

now by remainder theorm

R=f(a)

0=f(-3)

0=(-3)² + 6(-3)²-(-3)+ 5 + P

0= 9 + 54 + 3 + 5 + P

-71=P

therefore, -71 should be added.

Hope you understand

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What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)​

What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)