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AleksandrR [38]
2 years ago
12

What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)​

Mathematics
1 answer:
maxonik [38]2 years ago
4 0

Let f(x) = x² + 6x²-x+ 5 then ,

number to be added be P

then,

f(x) = x² + 6x²-x+ 5 +P

According to the qn,

(x+3) is exactly divisible by zero then,

R=0

comparing .. we get a= -3

now by remainder theorm

R=f(a)

0=f(-3)

0=(-3)² + 6(-3)²-(-3)+ 5 + P

0= 9 + 54 + 3 + 5 + P

-71=P

therefore, -71 should be added.

Hope you understand

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Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long

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r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2

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2 years ago
6 out of 18 in a fraction
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7 0
3 years ago
Read 2 more answers
Solve the inequality<br> -3(j+3)+9j&lt;-15
MAXImum [283]
Simplify
−
3
(
j
+
3
)
+
9
j
-
3
(
j
+
3
)
+
9
j
.
Tap for fewer steps...
Simplify each term.
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−
3
j
−
9
+
9
j
<
−
15
-
3
j
-
9
+
9
j
<
-
15
Add
−
3
j
-
3
j
and
9
j
9
j
.
6
j
−
9
<
−
15
6
j
-
9
<
-
15
Move all terms not containing
j
j
to the right side of the inequality.
Tap for fewer steps...
Add
9
9
to both sides of the inequality.
6
j
<
−
15
+
9
6
j
<
-
15
+
9
Add
−
15
-
15
and
9
9
.
6
j
<
−
6
6
j
<
-
6
Divide each term in
6
j
<
−
6
6
j
<
-
6
by
6
6
and simplify.
Tap for fewer steps...
Divide each term in
6
j
<
−
6
6
j
<
-
6
by
6
6
.
6
j
6
<
−
6
6
6
j
6
<
-
6
6
Simplify the left side.
Tap for more steps...
j
<
−
6
6
j
<
-
6
6
Simplify the right side.
Tap for more steps...
j
<
−
1
j
<
-
1
The result can be shown in multiple forms.
Inequality Form:
j
<
−
1
j
<
-
1
Interval Notation:
(
−
∞
,
−
1
)
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3 years ago
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Neko [114]
First you would need to find out how many 9 payments of 58$ would be and that is 522. Then you would need to subtract the 522 and the 480 and your answer would be 42$ so the interest would be 42$
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