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AleksandrR [38]
2 years ago
12

What must be added to x² + 6x²-x+ 5 to make it exact divisible by (x + 3)​

Mathematics
1 answer:
maxonik [38]2 years ago
4 0

Let f(x) = x² + 6x²-x+ 5 then ,

number to be added be P

then,

f(x) = x² + 6x²-x+ 5 +P

According to the qn,

(x+3) is exactly divisible by zero then,

R=0

comparing .. we get a= -3

now by remainder theorm

R=f(a)

0=f(-3)

0=(-3)² + 6(-3)²-(-3)+ 5 + P

0= 9 + 54 + 3 + 5 + P

-71=P

therefore, -71 should be added.

Hope you understand

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Answer:

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Vertex at (h, k) :  

(y - k)2  =  4a(x - h) (opens right, a > 0)

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Equation of a Parabola in Vertex form

Vertex at Origin :  

y  =  ax2 (opens up, a > 0)

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Step-by-step explanation:

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Answer:

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