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Radda [10]
3 years ago
5

An artist is making a rectangular canvas for a custom painting. The canvas has a width of 9 1/2 feet and a length of 13 1/2 feet

. What is the area of the canvas in square feet?
Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

The area of the canvas is 128\frac{1}{2} sq feet.

Step-by-step explanation:

Given,

The length (l) of the canvas = 13\frac{1}{2} feet

The width (b) of the canvas = 9\frac{1}{2} feet

To find the area of the canvas.

Formula

The area of the rectangle = l×b sq ft

Here,

The area of the canvas = 13\frac{1}{2}×9\frac{1}{2} sq feet

= \frac{27}{2}×\frac{19}{2} sq feet = \frac{513}{4} sq feet = 128\frac{1}{2} sq feet

The area of the canvas is 128\frac{1}{2} sq feet.

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3 years ago
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irina1246 [14]

Answer:

x= √10/2

Step-by-step explanation:

if you use trig. functions:

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the sides are x, and hypothenuse must be x√2 in this type of triangles so in our case:

x√2 = √5 divide both sides by √2

x= √5/√2 multiply by √2/√2 which =1 and help us get rid of the radical from the denominator

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6 0
3 years ago
The perimeter of a rectangle is 102 inches. The length is 5 inches greater than the width.
Mazyrski [523]

Answer:

w = 23

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Step-by-step explanation:

w = width

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102 = 2(2w+5)

Divide each side by 2

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Subtract 5

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Divide by 2

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5 0
3 years ago
Read 2 more answers
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3 0
4 years ago
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