Answer:
Let the sides be a and b
a^2 + b^2 = c^2 = 29^2 = 841
a^2 + (a + 1)^2 = 841
a^2 + a^2 + 2 a + 1 = 841
2 a^2 + 2 a = 840
a (a + 1) = 420
21 * 20 = 420 trial and error
So the sides are 20 and 21
20^2 + 21^2 = 29^2
Answer:
Yes
General Formulas and Concepts:
<u>Algebra I</u>
- Reading a coordinate graph
- Coordinates (x, y)
- Solving inequalities
Step-by-step explanation:
When we plot (-2, -4) onto the graph, we can envision that the point is within the shaded region of the graphed line.
∴ (-2, -4) would be a solution.
Well, we know the last three numbers are:
3 (ones)
6 (tens)
7 (hundreds)
The next set is:
9 (thousands)
3 (ten thousands)
0 (hundred thousands)
And finally:
6 (millions)
5 (ten millions)
6 (hundred millions)
So we know that 5 is in ten millions.
Answer:
61°
Step-by-step explanation:
In order for triangle LMN and PQR to be congruent, angle M and angle Q must equal. thus, we can set 2x-26=x+16
with basic algebraic manipulation, x=42. we then plug it back into the angle M or Q, getting angle M/Q= 58°
since this is a isoceles, the 2 base angle are identical, so 180= 58+2(angle P)
thus, angle P= 61
Answer:
these triangles some is 90°.
72°+2x=90°
2x=90°-72
2x=18
x=18/2
x=9
