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belka [17]
3 years ago
7

What is the area of the blue shaded region​???????

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

Step-by-step explanation:

22/7x7^2=154

22/7x3^2=28(approx)

154-28=126

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Which rational graph has a minimum near x=-2 and a horizontal asymptote at y=1?
Arada [10]

Answer:

Graph A.

Step-by-step explanation:

The graph has a local minimum around x=-2 since it slightly curves downwards around this region. Moreover, the graph of the rational function has a horizontal asymptote at y=1 since the graph approaches this horizontal line but never touches nor crosses it

7 0
3 years ago
The standard form of the number represented by the Roman numeral MXCIV is
Assoli18 [71]

Answer:

1094

Step-by-step explanation:

4 0
2 years ago
80. At the gym Suppose that 10% of adults belong to
maria [59]

Answer:

4% of all adults go to a health club at least twice a week

Step-by-step explanation:

the proportion of adults who belong to health clubs is 10% that is 0.10

the proportion of these adults (health club members) who go to the club at least twice a week is 40%, which is 0.40.

Thus, the proportion of all adults who go to a health club at least twice a week is

0.10 × 0.40 = 0.04, that is 4%

6 0
3 years ago
0.86 is 3.06 % of what number (Round to the nearest hundredth.)
polet [3.4K]

Answer:

Let the number be x

3.06% = 0.0306

The above statement is written as

0.0306x = 0.86

Divide both sides by 0.0306

x = 0.86/0.0306

<h2>x = 28.10</h2>

Hope this helps you

4 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
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