Problem 1: 21 divided by 189 problem2: 33 divided by 8,580
2 answers:
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A) At $3,300 for 600 seats, the average price per seat is 3300/600 = $5.50. The mix of tickets that results in that average can be found using an X diagram as shown below. The numbers on the right are the differences along the diagonals. When they are multiplied by 2, they add to 600. This shows that the required sales for revenue of $3,300 are
200 adult tickets
400 student tickets
b) When 3 student tickets are sold for each adult ticket, the average seat price is
(3*$4.50 +7.50)/4 = $5.25
Then the shortfall in revenue is ...
$3,300 -480*$5.25 = $780
Hope I was able to help!<3 mark brainly I would appreciate it!:)
200 adult tickets
400 student tickets
b) When 3 student tickets are sold for each adult ticket, the average seat price is
(3*$4.50 +7.50)/4 = $5.25
Then the shortfall in revenue is ...
$3,300 -480*$5.25 = $780
Hope I was able to help!<3 mark brainly I would appreciate it!:)
Answer: a) 0.8413, b) 0.9987.
Step-by-step explanation:
Since we have given that
Mean = 3 pounds
Standard deviation = 0.25 pounds
n = 28 bricks
So, (a) What is the probability that all the bricks in the sample exceed 2.75 pounds?
b) What is the probability that the heaviest brick in the sample exceeds 3.75 pounds?
Hence, a) 0.8413, b) 0.9987.