I THINK ITS B or A BUT I AM NOT SURE
The approximate length of side a is 9.12 in. The correct option is B. 9.12 in
<h3>Law of Sines </h3>
From the question, we are to determine the approximate length of side a
From the given information, we have that
m∠B = 114°, m∠C = 22°
Thus,
m∠A = 180° - (114° + 22°)
m∠A = 180° - 136°
m∠A = 44°
Now,
From the law of sines, we have that
a/sinA = b/sinB
Then,
a/sin44° = 12/sin114°
a = (12 ×sin44°)/sin114°
a = 9.12 in
Hence, the approximate length of side a is 9.12 in. The correct option is B. 9.12 in
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Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.
Answer: x=15
Step-by-step explanation: