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Lesechka [4]
3 years ago
7

Very urgent... I need it right now.. please help me with explanation!

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

a) Water height, H(g) = 8g^2 + 3g -4 - [9g^2 -2g -5] = 8g^2 + 3g -4 -9g^2 + 2g +5 = -g^2 +5g +1

b) g = 1

H(g) = -(1)^2 + 5(1) + 1 = -1 + 5 + 1 = 5

g=2

H(g) = -(2)^2 + 5(2) + 1 = -4 + 10 + 1 = 7

g=3

H(g) = -(3)^2 + 5(3) + 1 = -9 +15 +1 = 5

c) Greatest height

Find the vertex of the parabole

The vertex is at the mid point between the two roots.

To find the roots you can use the quadratic equation

The result is g = 5/2 + [√29]/2 and g = 5/2 - [√29]/2

The middle poin is 5/2 = 2.5

Now find H(2.5) = -(2.5)^2 + 5(2.5) + 1 = 7.5 ≈ 7.3

hope this helps

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A. a(t)=16pi(t^2)
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3 years ago
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2. Faith opens a credit card with an APR of 16.50% compounded monthly. How much is charged in interest this month if her
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14.44 (Letter D)

Step-by-step explanation:

The answer is 14.44

Hopefully its correct!!!

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A submarine sandwich 1.5 feet long is cut into 0.25 pieces. how many pieces will there be
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4 0
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Mr. Suárez wants to paint his storage shed. He needs to calculate the lateral surface area of the shed so
astraxan [27]

Answer:

Lateral surface area of the storage shed = 336 ft²

Step-by-step explanation:

The shed is in the shape of a rectangular prism. The lateral surface area of the storage shed can be calculated below. The lateral area is the sides of the prism.

lateral area of a rectangular prism = 2h (l + w)

where

l = length

h = height

w = width

h = 8 ft

l = 14 ft

w = 7 ft

lateral area of a rectangular prism = 2h (l + w)

lateral area of a rectangular prism = 2 × 8 × (14 + 7)

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7 0
2 years ago
When two six-sided dice are rolled, there are 36 possible outcomes. Find the probability that the sum is not 5.
zaharov [31]

Answer:

p(Not\ 5) = \frac{8}{9}

Step-by-step explanation:

Given:

Txo six-sided dice are rolled.

Total number of outcomes n(S) = 36

We need to find the probability that the sum is not equal to 5 p(Not 5).

Solution:

Using probability formula.

P(E)=\frac{n(E)}{n(S)}  ----------------(1)

Where:

n(E) is the number of outcomes favourable to E.

n(S) is the total number of equally likely outcomes.

The sum of two six-sided dice roll outcome is equal to 5 as.

Outcome as 5: {(1,4), (2,3), (3,2), (4,1)}

So, the total favourable events n(E) = 4

Now, we substitute n(E) and n(s) in equation 1.

P(5)=\frac{4}{36}

p(5) = \frac{1}{9}

Using formula.

p(Not\ E) + p(E) = 1

p(Not\ 5) + p(5) = 1

Now we substitute p(5) in above equation.

p(Not\ 5) + \frac{1}{9} = 1

p(Not\ 5) = 1-\frac{1}{9}

p(Not\ 5) = \frac{9-1}{9}

p(Not\ 5) = \frac{8}{9}

Therefore, the sum of two six-sided dice roll outcome is not equal to 5.

p(Not\ 5) = \frac{8}{9}

6 0
3 years ago
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