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3 years ago

NOT TO

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

Answer:

455.1 cm²

Step-by-step explanation:

The two containers have the following;

<u>Large container</u>

Volume : 3456 cm³

Surface area : 1024 cm²

<u>Small container</u>

Volume : 1458 cm³

Surface area : ?

If the two containers are mathematically similar then first find the volume scale factor

Volume of large/ volume of small

3456/1024 = 3.375

Length scale factor will be cube root of volume scale factor

∛3.375 = 1.5

Area scale factor is a square of the length scale factor

=1.5² = 2.25

=Surface area of the small container will be :

Larger area = 2.25 * small area

1024 = 2.25 * small area

1024/2.25 = small area

Surface area of the smaller container 455.1 cm².

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nexus9112 [7]

Answer:

y = 4x + 32

Step-by-step explanation:

Given: Temperature at sunrise = 32°F

y is the temperature after x hours of sunrise

Temperature change is 4°F/hour.

The equation of a line in slope intercept form is given by

y = mx +c

where m is the slope, which is the change in value of y to the value of x

and c is the value of y at x = 0

At sunrise, x =0 and y =32

∴ c = 32

Also we see that the change in temperature to that of time is 4/1 = 4

∴ m = 4

Substituting the values of m and c in the equation of line, we have

y = 4x +32

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3 years ago

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sergiy2304 [10]

Answer: d. 73,15

Step-by-step explanation:

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2 years ago

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Alexxandr [17]

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6 0

3 years ago

let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep

Nutka1998 [239]

Answer with Step-by-step explanation:

We are given that

$x_1,x_2$ and $x_3$ are linearly independent.

By definition of linear independent there exits three scalar $a_1,a_2$ and $a_3$ such that

$a_1x_1+a_2x_2+a_3x_3=0$

Where $a_1=a_2=a_3=0$

$y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1$

We have to prove that $y_1,y_2$ and $y_3$ are linearly independent.

Let $b_1,b_2$ and $b_3$ such that

$b_1y_1+b_2y_2+b_3y_3=0$

$b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0$

$b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0$

$(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0$

$b_1+b_3=0$

$b_1=-b_3$ ...(1)

$b_1+b_2=0$

$b_1=-b_2$ ..(2)

$b_2+b_3=0$

$b_2=-b_3$ ..(3)

Because $x_1,x_2$ and $x_3$ are linearly independent.

From equation (1) and (3)

$b_1=b_2$ ...(4)

Adding equation (2) and (4)

$2b_1==0$

$b_1=0$

From equation (1) and (2)

$b_3=0,b_2=0,b_3=0$

Hence, $y_1,y_2$ and $y_3$ area linearly independent.

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3 years ago

A school has 63% percent girls and 37%, percent boys. If 23%, percent of the girls wears contacts and 42%, percent of the boys w

Degger [83]

Answer:

30% students

Step-by-step explanation:

Let x be the number of total students of a school.

63% are girls then total number of girls = (0.63)x

37% are boys then total number of boys = ( 0.37)x

Now 23% of girls wear contacts then total number of girls

= (0.63x) × 0.23

= (0.1449x)

And 42% of boys wear contacts then total number of boys wearing contacts

= (0.37x) ( 0.42)

= (0.1554)x

Total students wears contacts = ( 0.1449x) + (0.1554x)

= (0.3003x)

Percentage of students wear contacts = $\frac{\text{total students wear contacts}}{\text{total students in school}}$ × 100

= $\frac{0.03003x}{x}$ × 100

= 30%

All 30% students wear contacts.

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3 years ago