| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
Hello!
You subtract the amount of flour you started with by the amount you used
2.250 - 0.725 = 1.525
The answer is 1.525 kilograms
Hope this helps!
Answer:
62,160 cubic feet
Step-by-step explanation:
To solve this problem, we can use a percentage formula as shown below:
<em>P = initial value</em>
<em>r = rate</em>
Now lets plug in the values given in the question:
62,160
This means that the volume of the warehouse after the addition will be 62,160 cubic feet.
Let's take the percentage as x
(x / 100) * 5 = 0.35
x / 100 = 0.07
x = 7
therefore the percentage is 7%
