Answer:
<DCA and <BCF
Step-by-step explanation:
The vertically opposite angles are the angles <DCA and <BCF. These angles are always equal.
- When two lines cross, two angles that are vertical two one another are equal.
- They are know as vertically opposite angles.
- When two straight lines cross each other, four angles are produced.
- The two vertically opposite have the same values.
Answer:
The fish is 2.25 ft above the surface at 0.375 seconds
Step-by-step explanation:
Given:
y=-16x^2+12x
x=0.375 seconds
Substitute x=0.375 into the equation
y=-16x^2+12x
= -16(0.375)^2 +12(0.375
= -16(0.140625) + 4.5
= -2.25 + 4.5
= 2.25
y=2.25 ft
The fish is 2.25 ft above the surface at 0.375 seconds
Answer:
factor is the answer
Step-by-step explanation:
I took the test
Answer:
The average number of visitors per day is 272.
Step-by-step explanation:
Total number of visitors in the zoo in a year = 98,464
Now,we know that 1 YEAR = 365 DAYS
Also, the zoo was closed on thanksgiving, Christmas, and New Year's Eve
So, the Number of days zoo was open = Total Days in year - 3 days
= 365 - 3 = 362 days
⇒Number of visitors in 362 days = 98,464
So, 
or, the number of people visiting per day is 272.
Hence, the average number of visitors per day is 272.
Answer: The number is 26.
Step-by-step explanation:
We know that:
The nth term of a sequence is 3n²-1
The nth term of a different sequence is 30–n²
We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.
we get:
3n²- 1 = 30–m²
Notice that as n increases, the terms of the first sequence also increase.
And as n increases, the terms of the second sequence decrease.
One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.
if m = 1, then:
3n²- 1 = 30–1²
3n²- 1 = 29
3n² = 30
n² = 30/3 = 10
n² = 10
There is no integer n such that n² = 10
now let's try with m = 2, then:
3n²- 1 = 30–2² = 30 - 4
3n²- 1 = 26
3n² = 26 + 1 = 27
n² = 27/3 = 9
n² = 9
n = √9 = 3
So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.
the number is:
3*(3)² - 1 = 26
30 - 2² = 26
The number that belongs to both sequences is 26.
