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3 years ago

Find the solution for the equation. n+14=25

Mathematics

2 answers:

RoseWind [281]3 years ago

6 0

Answer:

n=11

Step-by-step explanation:

rearrange the formula

move 14 to the other side making it negative

n+14=25

n=25-14

then calculate

n= 11

MAVERICK [17]3 years ago

3 0

Answer:

n=11

Step-by-step explanation:

All we need to do for this equation is combine like terms. In this case we need to subtract 14 from 25:

25-14=11

Now what we're left with is the answer.

n=11

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The sum of twice a number and 6

Allushta [10]

Answer:

The answer to your question is 4

The sum of twice a number and 6 is 4.

3 0

3 years ago

In 2012, the population of a city was 5.69 million. The exponential growth rate was 2.87% per year. a) Find the exponential g

Angelina_Jolie [31]

Answer:

a) The exponential growth function

P(t) = 5,690,000(1.0287)^t

b) 6,742,868.7374 million

c) 12.04 years

d) 2439.0243902

Step-by-step explanation:

In 2012, the population of a city was 5.69 million. The exponential growth rate was 2.87% per year.

The formula for exponential growth is given as:

P(t) = Po( 1 + r) ^t

Where P = Population size after time t

Po = Initial population size

r = Growth rate in percentage

t= time in years

a) Find the exponential growth function.

P(t) = Population size after time t

Po = Initial population size = 5.69 million

r = Growth rate in percentage = 2.87% = 0.0287

t= time in years

The Exponential growth function

P(t) = 5,690,000(1 + 0.0287)^t

P(t) = 5,690,000(1.0287)^t

b) Estimate the population of the city in 2018.

From 2012 to 2018 = 6 years

t = 6 years

Hence,

P(t) = Po( 1 + r) ^t

P(t) = 5,690,000(1 + 0.0287)^6

P(t) = 5,690,000(1.0287)^6

P(t) = 6,742,868.7374 million

c) When will the population of the city be 8 million?

P(t) = 8,000,000

P(t) = Po( 1 + r) ^t

P(t) = 5,690,000(1 + 0.0287)^t

8,000,000 = 5,690,000(1 + 0.0287)^t

8,000,000 = 5,690,000(1.0287)^t

Divide both sides by 5,690,000

8,000,00/5,690,000 = 5,690,000(1.0287)^t/5,690,000

= 1.4059753954 = 1.0287^t

Take logarithm of both sides

log 1.4059753954 = log 1.0287^t

Log 1.4059753954 =t Log 1.0287

t = Log 1.4059753954/Log 1.0287

t = 12.041740264

t = 12.04 years

d) Find the doubling time.

The formula is given as 70/Growth rate

= 70/0.0287

= 2439.0243902

4 0

2 years ago

The chances of a tax return being audited are about 21 in 1 comma 000 if an income is less than $100,000 and 29 in 1 comma 000

vladimir2022 [97]

Answer:

a) p=0.021

b) p=0.029

c) Exactly one audit: P=0.0965

More than one audit: P=0.0042

Step-by-step explanation:

a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:

$p_1=\dfrac{21}{1,000}=0.021$

If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:

$p_2=\dfrac{29}{1,000}=0.029$

b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:

$P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\$

There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.

To calculate the probability that more than one will be audited, we use the same distribution:

$P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^{0}q^{5}=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042$

There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.

8 0

3 years ago

Write an expression that is equivalent to 2x2 - 2x + 7?

den301095 [7]

Answer:

2x +7

Step-by-step explanation:

2x2 is multiplication , so u multiply ,minus the 2x would be 4x -2x , so it will give 2x + 7 as final asnwer

4 0

3 years ago

Read 2 more answers

Given that (x - 1) is a factor of x4 + 2x3 - 2x - 1, what are the solutions of x4 + 2x3 - 2x - 1 = 0? A. -2, 0, 1 B. -1, 0, 1 C.

noname [10]

Answer:

Step-by-step explanation:

If x-1 is a factor of x⁴ + 2x³ - 2x - 1, then x-1 =0 is a factor

if x-1 = 0

x = 1

To get other factors we will divide the polynomial by x-1

Find the division in the attachment

x⁴ + 2x³ - 2x - 1,/x-1 = x³ +3x²+ 3x + 1,

let x = -1 be a factor of the resulting expression

f(-1) = (-1)³ +3(-1)²+ 3(-1) + 1

f(-1) = -1 +3(1)-3 + 1

f(-1) =-1+1-3+3

f(-1) = 0

Since f(-1) =0, hence x+1 is a factor of the resulting polynomial'

Dividing x³ +3x²+ 3x + 1, by x+1 to reduce the power of the polynomial

x³ +3x²+ 3x + 1/x+1 = x²+2x+1

Factorizing x²+2x+1

= x²+2x+1

=x²+x+x+1

= x(x+1)+1(x+1)

= (x+1)(x+1)

if the function is equal to zero

x+1 = 0 and x+1 = 0

x = -1 twice

Hence the solutions to the polynomial are 1 and -1(three times)

4 0

3 years ago