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horsena [70]
3 years ago
8

Write an equivalent expression for 5(2x + y - 3z) by modeling and using the distributive property.

Mathematics
2 answers:
docker41 [41]3 years ago
7 0

Answer:

10x + 5y - 15z

Step-by-step explanation:

5(2x + y - 3z)

To get the equivalent expression we apply distributive property

a(x+b)= ax+ab

Using distributive property we distribute the number inside the parenthesis  Distribute 5 inside the parenthesis

5 times 2x becomes 10x

5 times y becomes 5y

5 times -3z becomes -15z

5(2x + y - 3z)

10x + 5y - 15z

soldi70 [24.7K]3 years ago
5 0

The answer is 10x + 5y - 15z

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Step-by-step explanation:

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<u>\frac{1}{7}   \div 3</u>

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2 years ago
A long distance telephone company offer two plans . The deluxe plan cost $30 a month and offers unlimited long distance calling.
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399 minutes a month

Step-by-step explanation:

As I understand the question the answer would, in other words, be how many minutes you can long-distance call with the economy plan for under $30.

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3 years ago
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
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Step-by-step explanation:

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4 years ago
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