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jenyasd209 [6]
3 years ago
6

Ramòn bought a dozen ears of corn for $1.80. What was the cost of each ear of corn?

Mathematics
2 answers:
Georgia [21]3 years ago
5 0
Your answer would be15 cents because 12 divided by 1.80 equals .15 so your answer would be 15 cents
Vikentia [17]3 years ago
3 0
One dozen= 12

$1.80/12= $0.15 each

Final answer: $0.15
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a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is
irakobra [83]

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer


4 0
3 years ago
2x + 4y = 30 x = y - 6
Rufina [12.5K]

Answer:

x = 1 ,  y = 7

Step-by-step explanation:

4 0
2 years ago
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Which of the following is a binomial with degree 4?
wel

Answer:

the answer is A

Step-by-step explanation:

hope it's help

4 0
3 years ago
Elias was given a lock for his school locker. The lock contains numbers between
daser333 [38]

Answer:

34,220

Step-by-step explanation:

Because order doesn't matter, but the numbers can't be repeated, we need to find the number of combinations where 3 individual numbers can be chosen out of 60 possible numbers using the binomial coefficient:

\binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{60}{3}=\frac{60!}{3!(60-3)!}\\\\\binom{60}{3}=\frac{60!}{3!(57)!}\\\\\binom{60}{3}=\frac{60*59*58}{3*2*1}\\ \\\binom{60}{3}=34220

Thus, Elias can make 34,220 unique 3-number codes given 60 different numbers.

6 0
2 years ago
Do 5/7 and 30/42 form a proportion
GREYUIT [131]
5/7
6*5/6*7
30/42

30/42 = 30/42

Yes, 5/7 and 30/42 form a proportion.
4 0
3 years ago
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