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puteri [66]
3 years ago
6

The probability that a company will launch the product A and B are 0.45 and 0.60 respectively, in main while, probability that b

oth products launched, is 0.35. what is the probability that Neither will of these products launch ? At least one product will be launched ?
Mathematics
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

a) what is the probability that Neither will of these products launch ?

= 0.30

b) At least one product will be launched ?

= 0.70

Step-by-step explanation:

From the above question, we have the following information:

P(A) = 0.45

P(B) = 0.60

P(A ∩ B) = P(A and B) launching = 0.35

Step 1

We find the Probability that A or B will launch

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

a) what is the probability that Neither will of these products launch ?

1 - Probability ( A or B will launch)

= 1 - 0.70

= 0.30

b)At least one product will be launched?

This is equivalent to the probability that A or B will be launched

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

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8 0
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The graph represents one side of the roof of a building.<br> The slope of the line is
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Answer:

The slope of the line is 7/2.

Step-by-step explanation:

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Therefore the slope of the line is 7/2.

7 0
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Which best describes the structure of the expression (5 ⋅ 46.4) − (3.2 ⋅ 13.7)
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~kaikers
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3 years ago
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What is the partial product for 652 x 4= 2,608
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To find out the answer of the two multiplied products with the help of partial products we separate into unit based numbers so as to, for easier calculation and simplification with units of zeroes. So, in this case we are given the product of 4 times of 652.

Here we need to expand this product of higher number to zeroes and take aside the added numbers to come back to the original multiple of a product. That is:

\huge{652}

\begin{bmatrix}652 \\ + \\ 0 \end{bmatrix}

We just separated and expanded the product to be multiplied by removing other units following it. Same goes for other units at Hundredth, tenth and unitary position.

Therefore,

\begin{bmatrix}600 \\ + \\ 52 \end{bmatrix}

For tenth term.

\begin{bmatrix}50 \\ + \\ 2 \end{bmatrix}

The terms after splitting and expanding the product before multiplication is:

\begin{bmatrix}600 \\ 50 \\ 2 \end{bmatrix}

Multiply the product elements in individual manner and add the elements forged by individual multiplication to get the required solution.

\therefore \quad \begin{bmatrix}600 \times 4 \\ 50 \times 4 \\ 2 \times 4 \end{bmatrix}

\begin{bmatrix}600 \times 4 \\ + \\ 200 \\ + \\ 2 \times 8 \end{bmatrix}

\begin{bmatrix}2400 \\ + \\ 200 \\ + \\ 2 \times 8 \end{bmatrix}

\begin{bmatrix}2600 \\ + \\ 8 \end{bmatrix}

\boxed{\mathbf{Final \: \: Answer \: = \: 2,608}}

Hope it helps.
8 0
3 years ago
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