Answer:
∠2 ≅ ∠B
Step-by-step explanation:
Let the triangle be ABC,
Given that,
∠A = 50°
∠C = 65°
Using angle-sum property of the triangle,
∠A + ∠B + ∠C = 180°
50° + ∠B + 65° = 180°
∵ ∠B = 65° ...(i)
A.T.Q.
Two horizontal lines are extended making 3 angles. Two angles out of them are 50° and 65°.
Since the adjacent angles comprising a straight line is equals to 180°.
so,
∠2 + 50° + 65° = 180°
∠2 + 115° = 180°
∠2 = 180° - 115°
∵ ∠2 = 65° ...(ii)
Using (i) and (ii),
∠2 ≅ ∠B
Therefore, ∠2 and ∠B are congruent to one another.
Number 9 would be 64 because you as up each pond
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
Answer:
standard form: y = -x^2 + 15x
Answer:
Step-by-step explanation:
A, x=31
E, b=11
N, m=61
Y, b=15
I, a=80
G, k=-78
U, x=-13
R, u=88
O, y=13
A, w=104
H, d=-7
V, n=1/36
Sorry, don't want to give away all the answers!
Hope this helps!!!
