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3 years ago

What is the fifth term of the sequence 4/3, 8/3, 4, 16/3 ?

Mathematics

2 answers:

Komok [63]3 years ago

4 0

Answer:

$\frac{20}{3}$

Step-by-step explanation:

Note the consecutive terms in the sequence have a common difference, that is

$\frac{8}{3}$ - $\frac{4}{3}$ = 4 - $\frac{4}{3}$ = $\frac{16}{3}$ - 4 = $\frac{4}{3}$

This indicates the sequence is arithmetic with d = $\frac{4}{3}$

To find the next term in the sequence add d to the previous term, thus

$a_{5}$ = $\frac{16}{3}$ + $\frac{4}{3}$ = $\frac{20}{3}$

kupik [55]3 years ago

3 0

Answer:

20/3

Step-by-step explanation:

add four t ok top one and keep the 3 down

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For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

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case 2) f(0) = 4 and g(–2) = 4

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

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case 3) f(2) = 0 and g(–2) = 0

For x=2-----> find the value of f(2) in the graph-----> f(2)=0

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

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