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inysia [295]
2 years ago
7

Olivia typed 36-word paragraph in 2/3 minute. what is her typing speed, in words per minute?​

Mathematics
1 answer:
Pepsi [2]2 years ago
7 0

Answer:

Olivia typed speed per minutes is 54 words

Step-by-step explanation:

Given:

Olivia typed 36 word in 2/3

Solution:

By Unitary method, calculate the speed of typing by Olivia as-

2/3 Minutes → 36 Words

1 Minutes → 36 ÷(2/3) Words

1 Minutes → 36x3÷2 Words

1 Minutes → 54 Words

Therefore Olivia typed speed is 54 word.

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Answer:

x  ≤  4

Step-by-step explanation:

6x + 3 ≤ 27        subtract 3 both sides

6x ≤ 24              divide 6 both sides

x ≤ 4                   There's your answer

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PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi
Irina18 [472]

Answer:

Question 1: P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}

Question 2:

A. P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

B. P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

C. P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

Step-by-step explanation:

Conditional probability is defined by

P(A|B)= \frac{P(A and B)}{P(B)}

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} }  = \frac{1}{2}

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

then

P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

so

P((YorZ) and B)= \frac{3}{16}

By definition,

P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

3 0
2 years ago
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olganol [36]

Answer:

7 horses and 8 chickens

Step-by-step explanation:

To solve this, first you would need to list out all of the available ratios. Then, find out how many legs are in each option.:

14 horses and 1 chicken = 58 legs

13 horses and 2 chickens = 56 legs

12 horses  and 3 chickens = etc.

11 horses and 4 chickens

10 horses and 5 chickens

9 horses and 6 chickens

8 horses and 7 chickens

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6 horses and 9 chickens

5 horses and 10 chickens

4 horses and 11 chickens

3 horses and 12 chickens

2 horses and 13 chickens

1 horses and 14 chickens

5 0
2 years ago
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