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nlexa [21]
3 years ago
11

Keep help me this is confusing. which equation is graphed on the line?

Mathematics
2 answers:
adoni [48]3 years ago
5 0

The answer is the last choice. Choice number 4!

Zepler [3.9K]3 years ago
4 0

<em>given</em>

y + 2 = - 3/2 ( x + 2 )

<em>distribute</em>

y + 2 = - 3/2x + 3

<em>subtract 2 from both sides</em>

y + 2 = - 3/2x + 3

...

y = - 3/2x + 3 - 2

<em>combine like terms</em>

y = - 3/2x + 1

answer:

y = - 3/2x + 1

the slope is - 3/2

the y intercept is + 1



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Someone please answer this
babymother [125]

Answer:

9.4m is the answer.

Step-by-step explanation:

a = 8m

b = 5m

c = ?

According to the Pythagoras theorem,

a² + b² = c²

8² + 5² = c²

64 + 25 = c²

89 = c²

c = 9.433

Rounding off,

c = 9.4m

4 0
3 years ago
Please help me I don’t have a lot of time
sp2606 [1]

Answer:

I believe the answer is d

3 0
3 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
2 years ago
Minimum and maximum value of 2n^2+5n-25=0
Alborosie
Equations don't have minimum or maximum, functions do.

Function y=2n^2+5n-25 has minimum -28.125, has no maximum.
8 0
3 years ago
What is the slope of the line containing (-2, 5) and (4,-4)?
Pachacha [2.7K]

Answer:

Option C is correct.

Step-by-step explanation:

<h2>slope \:  =  \:  \frac{y2 - y1}{x2 - x1}</h2><h3>=  \frac{ - 4 - (5)}{4 - (2)}</h3><h3>=  \frac{ - 9}{4 + 2}</h3><h3>=  \frac{ - 9}{6}</h3><h3>= \frac{3( - 3)}{3 - 2}</h3><h3>=  -  \frac{3}{2}</h3><h3>Hope it is helpful....</h3>
5 0
3 years ago
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