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nlexa [21]
3 years ago
11

Keep help me this is confusing. which equation is graphed on the line?

Mathematics
2 answers:
adoni [48]3 years ago
5 0

The answer is the last choice. Choice number 4!

Zepler [3.9K]3 years ago
4 0

<em>given</em>

y + 2 = - 3/2 ( x + 2 )

<em>distribute</em>

y + 2 = - 3/2x + 3

<em>subtract 2 from both sides</em>

y + 2 = - 3/2x + 3

...

y = - 3/2x + 3 - 2

<em>combine like terms</em>

y = - 3/2x + 1

answer:

y = - 3/2x + 1

the slope is - 3/2

the y intercept is + 1



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Which is an equation in point-slope form for the given point and slope?
xxMikexx [17]

Hi There!

Solution,

Point Slope Form: y - y1 = m(x - x1)

Now you have a reference equation of what the answer should look like.

By looking at the answer choices you can eliminate A.

Tip: When you have a negative number you are going to add. For Example, if you have -8, you will input x + 8 or y + 8.

Tip 2: When you have a positive number you are going to subtract. For Example, if you have 3 you will input x - 3 or y - 3.

We can eliminate B because its not subtracting 3.

We can also eliminate C because its not adding -8.

The best answer choice is D.

Answer,

y – 3 = 6(x + 8)

I hope you understand, so you can do this in the future on your own.

Hope This Helps :)

4 0
3 years ago
Which fraction has the greatest value 1/3 2/3 2/9 2/9
sdas [7]
2/3 has the greatest Value 



3 0
3 years ago
Read 2 more answers
Can anybody help me with this? <br> This question is confusing and I don't get it.
Lunna [17]

Answer:

JH = 8, GH = 12, and GJ = 10.6

Step-by-step explanation:

According to Midsegment Theorem, a segment that connects the midpoints of two sides of a triangle is half the length of the third side.

GH = ½ DE

JH = ½ DF

GJ = ½ EF

DE is 24, so GH = 12.

JH is half of DF.  Since G is the midpoint of DF, DG is also half of DF.  So JH = DG = 8.

GJ is half of EF.  Since H is the midpoint of EF, HE is also half of EF.  So GJ = HE = 10.6.

4 0
3 years ago
Select all the pairs of equivalent expressions.
iren2701 [21]

Answer:

\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

3 0
3 years ago
Which trigonometric functions are negative in the fourth (IV) quadrant?
anzhelika [568]
<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0
2 years ago
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