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DochEvi [55]
3 years ago
15

Let a, b, c, and d be nonzero real numbers. If the quadratic equation ax (cx + d) = –b (cx + d) is solved for x, which of the fo

llowing is a possible ratio of the 2 solutions?
Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

x_1=-\frac{b}a,x_2=-\frac{d}c

Step-by-step explanation:

Solving for x:

ax(cx + d) =-b(cx +d)\\ax(cx + d)+b(cx+d)=0\\(ax+b)(cx+d)=0

In this form is easy to identify the factors of the quadratic function: (ax+b)(cx+d). The two solutions are the values ​​that make each of the factors equals to zero.

ax_1+b=0\\ax_1=-b\\x_1=-\frac{b}a\\cx_2+d=0\\cx_2=-d\\x_2=-\frac{d}c

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