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DochEvi [55]
3 years ago
15

Let a, b, c, and d be nonzero real numbers. If the quadratic equation ax (cx + d) = –b (cx + d) is solved for x, which of the fo

llowing is a possible ratio of the 2 solutions?
Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

x_1=-\frac{b}a,x_2=-\frac{d}c

Step-by-step explanation:

Solving for x:

ax(cx + d) =-b(cx +d)\\ax(cx + d)+b(cx+d)=0\\(ax+b)(cx+d)=0

In this form is easy to identify the factors of the quadratic function: (ax+b)(cx+d). The two solutions are the values ​​that make each of the factors equals to zero.

ax_1+b=0\\ax_1=-b\\x_1=-\frac{b}a\\cx_2+d=0\\cx_2=-d\\x_2=-\frac{d}c

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Given that new DVDs are selling for $12 and used for $7, then Joseph is buying:
12·2 + 7<em>x </em>= 

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Decide if the following scenario involves a permutation or combination. Then find the number of possibilities. The student body
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735,130.

Step-by-step explanation:

The order of election of the 3 representatives does not matter so it is a combination.

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= 165! / 162! 3!

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= 735,130.

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3 years ago
Determine the value of the ?
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2 years ago
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Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
Expand and combine like terms (3z^5 +7z^2)^2
AVprozaik [17]

Answer:

\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }

Step-by-step explanation:

Since it's a perfect square, we can simply use the formula:

\displaystyle{(ax+by)^2 = a^2x^2+2abxy+b^2y^2}

Given the perfect square expression \displaystyle{(3z^5+7z^2)^2}. Apply perfect square formula:

\displaystyle{(3z^5+7z^2)^2 = 3^2(z^5)^2+2(3)(7)(z^5)(z^2) + 7^2(z^2)^2 }

Knowing laws of exponent is mandatory when it comes to algebra. Recall that:

\displaystyle{(a^m)^n = a^{mn}}\\\\\displaystyle{a^m \cdot a^n = a^{m+n}}

Apply laws of exponent to simplify the terms or expression:

\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }

Since there are no like-terms to do operation with (these terms have different degrees so they are not considered to be like-terms.) Therefore, the final answer is:

\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }

8 0
1 year ago
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