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pshichka [43]
2 years ago
6

The sum of the ages of Levi and Monique is 76 years. 8 years ago, Levi's age was 3 times Monique's age. How old is Levi now?

Mathematics
1 answer:
andreev551 [17]2 years ago
8 0

Answer:

Levi is 53 yrs now

Step-by-step explanation:

sum = 76yrs

Levi = 3x -8

Monique = x - 8

8yrs ago

sum= 76 - 8 - 8( the two 8s are from each of the two brothers).

      = 60yrs

Levi=3x

Monique=x

3x + x = 60

4x = 60

x = 15yrs

Levi = 3x

               = 15 x 3

               = 45 yrs(8yrs ago)

now = 45 + 8

       = 53yrs now

Monique = x

               = 15

now = 15 + 8

           23yrs now

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Natali5045456 [20]

Let's call a child's ticket c and an adult's ticket a. From this, we can say:

c + a = 116,

since 116 tickets are sold in total.


Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

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Given these values, we can say:

17000a + 12750c = 1653250,

since each adult ticket a costs 17,000 and each child's ticket c costs 12,750, and these costs sum to 1,653,250.


Now, we have two equations:

17000a + 12750c = 1653250

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Let's solve:

17000a + 12750c = 1653250

a = 116 - c

  • Find a on its own, which will allow us to substitute it into the first equation

17000(116 - c) + 12750a = 1653250

  • Substitute in 116 - c for a

1972000 - 17000c + 12750c = 1653250

  • Apply the Distributive Property

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4250c = 318750

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c = 75


We have now found that 75 child's tickets were sold. Thus,

75 + a = 116 \Rightarrow a = 116 - 75 = 41,

41 adult tickets were sold as well.


In sum, 41 adult tickets were sold along with 75 child tickets.

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