Answer:
the two angles are 55° each
Step-by-step explanation:
Let the two equal angles be y each
Therefore,
70° + y + y = 180°
Collect like terms
2y = 180 — 70
2y = 110
Divide both side by the coefficient of y i.e 2
y = 110/2
y = 55°
Therefore, the two angles are 55° each
Answer:
£910
Step-by-step explanation:
let 3x and 7x be the initial amounts in their accounts, then after alterations
Terry has 3x + 220
Faye has 7x - 300
After these changes the amounts are equal, hence
7x - 300 = 3x + 220 ( subtract 3x from both sides )
4x - 300 = 220 ( add 300 to both sides )
4x = 520 ( divide both sides by 4 )
x = 130
Faye initially had 7 × £130 = £910 in her account
Answer: In 5 years it will be worth £455
Step-by-step explanation:
Step 1
Given
The cost of the T.V. for Colin = £530.
The rate of depreciation per year = 3%
Time/ period = 5 years
Formulae to be used
F = P X (1 - r) ^ n
where
F = the future value after depreciation
P = the present value.
r =the interest rate per time period
n = the time/ periods
Step 2--- SOLVING
F = P X (1- r) ^ n
F= 530 x (1-0.03) ^ 5
=530 x 0.858734
=£455.129
Rounding up to the nearest penny where appropriate = £455
Answer:
(a)123 km/hr
(b)39 degrees
Step-by-step explanation:
Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.
Distance = Speed X Time
Therefore: PQ =50km/hr X 2 hr =100 km
It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.
Distance, QA=50km/hr X 2.5 hr =125 km
Using alternate angles in the diagram:
(a)First, we calculate the distance traveled, PA by plane Y.
Using Cosine rule
SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am
Time taken =1.5 hour
Therefore:
Average Speed of Y
(b)Flight Direction of Y
Using Law of Sines
![\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7B%5Csin%20P%7D%20%3D%5Cdfrac%7Bq%7D%7B%5Csin%20Q%7D%5C%5C%5Cdfrac%7B125%7D%7B%5Csin%20P%7D%20%3D%5Cdfrac%7B184.87%7D%7B%5Csin%20110%7D%5C%5C123%20%5Ctimes%20%5Csin%20P%3D125%20%5Ctimes%20%5Csin%20110%5C%5C%5Csin%20P%3D%28125%20%5Ctimes%20%5Csin%20110%29%20%5Cdiv%20184.87%5C%5CP%3D%5Carcsin%20%5B%28125%20%5Ctimes%20%5Csin%20110%29%20%5Cdiv%20184.87%5D%5C%5CP%3D39%5E%5Ccirc%20%24%20%28to%20the%20nearest%20degree%29)
The direction of flight Y to the nearest degree is 39 degrees.
The answer is B
15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution
