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Sergio [31]
3 years ago
14

Using the complete the square method, rewrite f(x) = x^2 -6x + 2 in vertex form

Mathematics
1 answer:
Tasya [4]3 years ago
4 0
F(x) = x^2 - 6x + 9 + (2 - 9)    -6/2 = -3.  square -3 = +9.  add  to the squaring portion and subtract it from f(x)

f(x) = (x-3)^2 -7

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The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard
I am Lyosha [343]

Answer:

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

p_v =P(Z>2.3)=1-P(Z  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

Step-by-step explanation:

1) Data given and notation  

\bar X=53.4 represent the sample mean

\sigma=12 represent the population standard deviation assumed

n=36 sample size  

\mu_o =48.8 represent the value that we want to test  

\alpha=0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:  

Null hypothesis:\mu \leq 48  

Alternative hypothesis:\mu > 48  

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3  

4)P-value  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.3)=1-P(Z  

5) Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.  

3 0
3 years ago
The slope of a hill next to a highway decreases 2 vertical feet for every 3 horizontal feet away from the highway.
Novay_Z [31]

Slope is the change in Y ( vertical) over the change in X( horizontal).

The slope would be -2 /3

You would multiply the horizontal distance by the slope:

-2/3 x 12 = -8

The answer would be D. v(h)=-2/3h, and the vertical distance is -8 feet.

8 0
3 years ago
What is -6 13/15 written as a decimal
Nikitich [7]
-6.86666666667 this is the answer for your question 
4 0
3 years ago
The test statistic of z=2.08 is obtained when testing the claim that p≠0.611. a. Identify the hypothesis test as being​ two-tail
krek1111 [17]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

When the two-tailed were testing then:

Null and alternative hypothesis:

H_0 : p = 0.611\\\\H_a : p \neq 0.611

Testing the statistics:

\to z = 2.08\\\\P-value = 0.0375\\\\\alpha = 0.01\\\\0.0375> 0.01\\\\P-value < \alpha\\\\

therefore, it fails to reject the null hypothesis.

8 0
3 years ago
If a line has a slope of 2 and contains the point (-2, 1), what is its equation in
Lapatulllka [165]

Answer:

D

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m = 2 and (a, b ) = (- 2, 1 ) , then

y - 1 = 2(x - (- 2)) , that is

y - 1 = 2(x + 2)

5 0
2 years ago
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