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Sergio [31]
3 years ago
14

Using the complete the square method, rewrite f(x) = x^2 -6x + 2 in vertex form

Mathematics
1 answer:
Tasya [4]3 years ago
4 0
F(x) = x^2 - 6x + 9 + (2 - 9)    -6/2 = -3.  square -3 = +9.  add  to the squaring portion and subtract it from f(x)

f(x) = (x-3)^2 -7

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I dont understand please help
DiKsa [7]

2 \frac{1}{2}+(-2\frac{1}{4})

This is equal to:

2\frac{1}{2}-2\frac{1}{4}

When you add a negative number, it turns into subtraction.

First, I would change it to mixed numbers:

\frac{5}{2}-\frac{9}{4}

Now, you need to change the denominators to make sure they are the same on both fractions. I changed the first fraction's denominator to 4 so they match. You can do this by multiplying the numerator by 2:

\frac{10}{4}-\frac{9}{4}

Now, you simply subtract:

10-9=1

1/4 is your answer.

I hope this helps :)

3 0
3 years ago
What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x
lora16 [44]
\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}

We can begin by rearranging this into multiplication:

\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}

Now we can factor the numerators and denominators:

\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}

The factors (x+4) and (x+2) cancel out, leaving us with:

\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}

Our answer comes out to be:

\frac{(x-4)^{2} }{(x+3)(x+1)} or \frac{ x^{2} -8x+16}{ x^{2}+4x+3 }

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4
4 0
3 years ago
Plsssssss answer fast
stellarik [79]
B, x=12 because 140-80=60, 60/5=12
8 0
3 years ago
Can somebody help me please
Veseljchak [2.6K]

Step-by-step explanation:

yes its ans is (3,3) fast you have see in x axis then y axis .so according to this we write 3 which lies in x- axis and then another 3 which lies in y-axis.

3 0
2 years ago
For a pair of similar triangles, corresponding sides are _____ congruent.
Novosadov [1.4K]
Never

they have the same ratio only
congruent triangles have equal sides
5 0
3 years ago
Read 2 more answers
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