Hello :
note :
<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
</span></span>in this exercice : a =0 b = 0 r =8
<span>the equation of the circle is : x²+y² = 64</span>
Answer:
Yes
Step-by-step explanation:
If you divide all the sides of the larger triangle by 3, it's equivalent to the sides of the smaller triangle. Therefore, they are similar.
The domain is the set of x-values of a function. The range is the set of y-values of a function.
You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31
2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25
3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16
4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13
5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1
The range is {31, 25, 16, 13, 1}.
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Answer: {31, 25, 16, 13, 1}
<span>NCn is always equal to 1. </span>