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sladkih [1.3K]
3 years ago
12

What is the midpoint of the segment shown below ?

Mathematics
2 answers:
nadezda [96]3 years ago
6 0

Answer:

D. (\frac{5}{2},\frac{-7}{2})

Step-by-step explanation:

We have been given length of a line segment on coordinate plane. We are asked to find the coordinates of midpoint of given segment.

The midpoint (M) of a line segment with endpoints (x_1,y_1) and (x_2,y_2) can be found using formula:

M(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}).

Upon substituting coordinates of our given points in above formula, we will get:

M(\frac{1+4}{2},\frac{-1+(-6)}{2})

M(\frac{5}{2},\frac{-7}{2})

Therefore, the midpoint of our given segment is (\frac{5}{2},\frac{-7}{2}) and option D is the correct choice.

Ivanshal [37]3 years ago
5 0

(1,-1) and (4,-6)

midpoint:

x = (1 + 4)/2 = 5/2

y = (-1 - 6)/2 = -7/2


Midpoint (5/2, -7/2)


Answer

D.

(5/2, -7/2)

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Answer:

15 lb

Step-by-step explanation:

let the current weight of the puppy be X, the  initial weight of the puppy is 4lb or \frac{2}{3}X-6\ lb, (6 lb less 2/3 X) .

#We equate the current weight to the initial weight to determine X:

4\ lb=\frac{2}{3}X-6\ lb\\\\10 \ lb=\frac{2}{3}X\\\\X=15

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3 years ago
What is the equaiton of the line that goes through the point (6,-1) and is parallel to the line represented by the equautions y=
mixas84 [53]

parallel lines have the same slope


The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"


They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3


You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6


So far we have y=-5/6x + b

We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"


Replace that on the equation y=-5/6x + b and you get

-1 = (-5/6)(6) + b

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4 = b

b = 4


We found b, or the y-intercept


Go back to the equation y = -5/6 x + b and replace this b with the b we just found


y = -5/6x + 4

6 0
3 years ago
What is the equation of a line that passes through the points `\left(-2\ ,\ 9\right)`and `\left(-4\ ,\ -4\right)`?
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Answer:

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3 0
3 years ago
100 points!!! Please full out all of these ASAP!!! Please show work!!!
Alex

Answer:

look below

Step-by-step explanation:

y = 2 (x + 3)^2 - 2

Geometric figure:  parabola

Alternate forms:

y = 2 (x + 2) (x + 4)

y = 2 (x^2 + 6 x + 8)

-2 x^2 - 12 x + y - 16 = 0

Expanded form:

y = 2 x^2 + 12 x + 16

Roots:

x = -4

x = -2

<u>Properties as a real function: </u>

Domain - R (all real numbers)

Range - {y element R : y>=-2}

Partial derivatives:

d/dx(2 (x + 3)^2 - 2) = 4 (x + 3)

d/dy(2 (x + 3)^2 - 2) = 0

Implicit derivatives:

(dx(y))/(dy) = 1/(12 + 4 x)

(dy(x))/(dx) = 4 (3 + x)

Global minimum:

min{2 (x + 3)^2 - 2} = -2 at x = -3

3 0
3 years ago
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torisob [31]
Yes.The second factor is the difference of 2 squares,
so the second factor alone becomes

(x² - 4) = (x + 2) (x - 2)
5 0
3 years ago
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