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1 answer:
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y = ()x -2 is the equation of the required line
Step-by-step explanation:
Step 1 :
Equation of the given line is 3x-2y=14
Re writing this in the form y = mx + c , we have
-2y = -3x +14
y = ()x - 7
The co efficient of x , m is the slope of the line. So for the given line the slope is
Step 2 :
We have to find equation of a line which is parallel to this line. All parallel lines will have the same slope. Hence the required line has a slope of .
Step 3 :
Equation of line with slope m and passing through a point () is
(y-) = m((x-
)
So equation of line passing through (-6,-11) and with a slope of is
(y-(-11)) = ( x - (-6))
y + 11 = ( x + 6)
y = ()x + 9 - 11
y = ()x -2
Step 4 :
Answer :
y = ()x -2 is the required equation
so notice above, the circle is centered at h,k or 0,0, the origin, and has a ratio of 5.
and y = 2, is just a horizontal line, check the picture below.
