Complete Question
A random sample of 300 circuits generated 13 defectives. a. Use the data to test

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Use α = 0.05. Find the P-value for the test
Answer:
The p-value is
Step-by-step explanation:
From the question we are told that
The sample size is n = 300
The number of defective circuits is k = 13
Generally the sample proportion of defective circuits is mathematically represented as

=> 
=> 
Generally the standard Error is mathematically represented as

=> 
=> 
Generally the test statistics is mathematically represented as

=> 
=> 
From the z table the area under the normal curve to the left corresponding to -0.5317 is

Generally the p-value is mathematically represented as

=> 
=>
Answer:
n=5
Step-by-step explanation:
by using
n=(an-a)/a+1
substituting values
n= 7.2-(-7.2)/3.6 +1
n=5
Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size and the estimate are given by:

Hence:


The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).
More can be learned about the z-distribution at brainly.com/question/25890103