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const2013 [10]
4 years ago
14

Do Aliens Exist? Let me know your thoughts about this topic.

Mathematics
2 answers:
satela [25.4K]4 years ago
8 0

Answer:

Aliens are considered anything that isn't from this planet. So I believe aliens do exist, yes. Why do I believe that? Well, there are other galaxies out there other than ours, and I'm sure other life forms exist in those galaxies. They may look like us or they may not, we may never know because they are billions of lightyears away. There may be other life forms in our galaxy besides what is here on Earth or that isn't necessarily from Earth. :)

worty [1.4K]4 years ago
6 0
I think they exist because the universe is infinitely expanding. even if theyre just tiny bacteria or more advanced than us, there has to be more than just us out there. the universe is too huge for life to only be created once.
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(i) {45 = (7 + 8)} - 3
OverLord2011 [107]

Step-by-step explanation:

45 = 15 - 3

45 = 12

45 - 12

= 33

6 0
3 years ago
A car dealership increased the price of a certain car by 11%. The original price was $42,200.
Nataly_w [17]

So, with percentages the easiest way is to multiply the 42200 by 0.11. After that you get (4642.00) < Answer to A  so you add 42200 to 4642 to get the new price. That should bring you to (46842.0) < Answer to B

5 0
3 years ago
7-3 Multiplying Binomials
Nataly [62]

Answer:

Step-by-step explanation:

Use FOIL method.First multiply (5x + 1) and (3x - 4). Then multiply (15x² - 17x - 4) by (x +2)

Volume of the rectangular prism = length *width * height

              = (5x + 1) (3x -4)(x +2)

              = [ 5x*3x + 5x*(-4)  + 1*3x + 1*(-4) ] (x + 2)

             = [15x² <u>- 20x + 3x</u> - 4] (x +2)    {Combine like terms}

             = [15x² - 17x - 4] (x + 2)

             =[15x² -17x - 4]*(x) + [15x² - 17x  -4]*2

            = [15x²*x - 17x*x - 4*x ]+ 15x²*2 - 17x *2  - 4*2

            = 15x³ - 17x² - 4x  + 30x² - 34x - 8

           = 15x³ <u>- 17x² + 30x²</u>  <u>- 4x - 34x </u>- 8    {Combine like terms}

           = 15x³ + 13x²  - 38x - 8

7 0
4 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
A building has a perimeter of 112 meters. Its area is 735 square meters. What are the dimensions of the building?
PSYCHO15rus [73]
The width is 35 meters and the length is 21 meters.
6 0
3 years ago
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