Step-by-step explanation:
45 = 15 - 3
45 = 12
45 - 12
= 33
So, with percentages the easiest way is to multiply the 42200 by 0.11. After that you get (4642.00) < Answer to A so you add 42200 to 4642 to get the new price. That should bring you to (46842.0) < Answer to B
Answer:
Step-by-step explanation:
Use FOIL method.First multiply (5x + 1) and (3x - 4). Then multiply (15x² - 17x - 4) by (x +2)
Volume of the rectangular prism = length *width * height
= (5x + 1) (3x -4)(x +2)
= [ 5x*3x + 5x*(-4) + 1*3x + 1*(-4) ] (x + 2)
= [15x² <u>- 20x + 3x</u> - 4] (x +2) {Combine like terms}
= [15x² - 17x - 4] (x + 2)
=[15x² -17x - 4]*(x) + [15x² - 17x -4]*2
= [15x²*x - 17x*x - 4*x ]+ 15x²*2 - 17x *2 - 4*2
= 15x³ - 17x² - 4x + 30x² - 34x - 8
= 15x³ <u>- 17x² + 30x²</u> <u>- 4x - 34x </u>- 8 {Combine like terms}
= 15x³ + 13x² - 38x - 8
Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

Class
Interval Midpoints
45-48 
49-52 
53-56 
57-60 
61-64 
65-68 
69-72 
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
The width is 35 meters and the length is 21 meters.