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NeX [460]
3 years ago
13

BEST ANSWER WILL GET MARKED BRAINIEST

Mathematics
2 answers:
expeople1 [14]3 years ago
7 0

Answer:

The formula for the area of a square is:

{length}^{2}  \: or \: length \:  \times  \: length

So, to work out the side lengths you should square root each area value:

\sqrt{1}  = 1

As 1 × 1 = 1

So the side lengths of the 1 unit area square is 1 unit.

\sqrt{9}  = 3

As 3 × 3 = 9

So the side lengths of the 9 units area square is 3 units.

\sqrt{16}  = 4

As 4 × 4 = 16

So the side lengths of the 16 units area square is 4 units.

\sqrt{25}  = 5

As 5 × 5 = 25

So the side lengths of the 25 units area square is 5 units.

Sloan [31]3 years ago
4 0

Answer:

1,1

3,3

4,4

5,5

Step-by-step explanation:

see picture

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Tamiku [17]
The blue line...
(1,2),(3,1)
slope = (1 - 2) / (3 - 1) = -1/2
there is a y int at (0,2.5) or (0,5/2)
it is shaded below the line....and it is a solid line
this inequality is :
y = -1/2x + 5/2
1/2x + y = 5/2
x + 2y = 5
x + 2y < = 5.....this is ur inequality


red line...
(0,4), (1,1)
slope = (1 - 4) / (1 - 0) = -3/1 = -3

there is a y int at (0,4)
it is shaded below the line...and it is a solid line
this inequality is :
y = -3x + 4
3x + y = 4
3x + y < = 4 ...this is ur inequality

summary :
ur 2 inequalities are : 
x + 2y < = 5 and 3x + y < = 4


4 0
4 years ago
If CDE ~ GDF, find ED
qaws [65]

Answer:

10

Step-by-step explanation:

\triangle CDE \sim \triangle GDF.. (given) \\\\\therefore \frac{CD}{GD} =\frac{DE}{DF}.. (csst) \\\\\therefore  \frac{15}{x+3} =\frac{3x+1}{4}\\\\ \therefore   \: 15 \times 4 = (x + 3)(3x + 1) \\  \\ \therefore   \: 60 = 3 {x}^{2}  + x + 9x + 3 \\  \\ \therefore  3 {x}^{2}  + 10x + 3 - 60 = 0 \\ \therefore  3 {x}^{2}  + 10x  - 57 = 0 \\ \therefore  3 {x}^{2}  + 19x - 9x  - 57 = 0 \\ \therefore   \: x(3x + 19) - 3(3x + 19) = 0 \\\therefore   \:  (3x + 19)(x - 3) = 0 \\ \therefore   \: 3x + 19 = 0 \:  \: or \:  \: x - 3 = 0 \\  \therefore   \: x =  -  \frac{19}{3}  \:  \: or \:  \: x = 3 \\  \because \: x \: can \: not \: be \:  - ve \\ \therefore   \: x = 3 \\ ED = 3x + 1 = 3 \times 3 + 1  \\ \huge \red{ \boxed{ ED= 10}}

7 0
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Answer:

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