Question

Hi! Can you help me answer this?

Answer 1

Answer:

$C'(x)=-\frac{148}{x^2}$

$R'(x)=-0.06$

Step-by-step explanation:

Marginal average Cost function:

$\frac{d}{dx}(\frac{148+6.3x}{x})=-\frac{148}{x^2}$

Marginal average Revenue function:

$\frac{d}{dx}(\frac{3x-0.06x}{x})=-0.06$

Answer 2

Answer:

Step-by-step explanation:

yess