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Ksenya-84 [330]
2 years ago
12

2/3(x-7= -2 help please

Mathematics
1 answer:
Pepsi [2]2 years ago
3 0
The answer you want is -10
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Yuki888 [10]

Answer:

I don't know how to do please let me I will try solve the question

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Take a point O on your notebook and draw circles of 3.6 cm, 4.5 cm and 5.3 cm , each having the same centre O.​
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to aage kya keru koi Q hai to bol

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3 years ago
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Use the distributive property to factor the expression. 12xy + 28xz
soldier1979 [14.2K]

Answer:

The factored equation would be 4x(3y + 7z)

Step-by-step explanation:

In order to find this, look for the greatest common factor and pull it out. Since both have factors of 4 and both have an x, we pull those out. We then divide each term by 4x to get what is left over.

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2 years ago
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Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
Which description is correct for the x-intercept(s) of Function A and Function B?
ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

Generally,

A straight line equation is given as

y = mx + c

Where,

m is the slope or gradient of the line

c is the intercept of y axis, when x = 0

Now,

Given the function A

g(x) = 0 7 0 2 -2

x = -2 3. 5 -1 0

So, we said the intercept c is when x = 0,

Therefore, in this case when x=0, g(x) = -2

Then, the intercept is -2 on y axis

Then, it has only one intercept, which is -2 on y-axis

To get the intercept on x axis, we will set y to zero,

In this case,

g(x) = 0, then, we have the intercept on x-axis to be -2 and 5

So it has 2-intercept on x axis, one positive and one negative

Given the function B

F(x) = |x| - 3

Comparing this to equation of a line, y= mx + c,

Then we notice that, the intercept is -3

Then, it has only one intercept which is -3 on y axis.

Now, to get the intercept on x axis, we will set f(x) = 0

F(x) = |x| - 3

0 = |x| - 3

Then, |x| = 3

Then, x = 3 or -x =3

Note that, |x| means x and -x

Then, x = 3 or x = -3

So it has also two intercept on the x axis, one positive and one negative.

Then, the third option is the correct option

Both functions have one negative and one positive x-intercept.

5 0
3 years ago
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