Answer:
Step-by-step explanation:
By using logarithms it becomes easier to solve this question because of the properties they have
From the property of logarithms
Take logarithms on both sides
Answer:
2
Step-by-step explanation:
It sounds like we are pretending A is the universe. The only numbers in our world are 1,2,3,4, and 5.
You are given B is all numbers greater than 2.
The complement of B would all the elements not listed in B.
The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.
The elements not in B are 1 and 2.
So B complement is {1,2}.
There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.
Answer:
Step-by-step explanation:
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Answer:
1. (x +1)(x - 1)
2. (x+5)(x-5)
3. (x+12)(x-12)
4. (x+14)(x-14)
5. (x+5)(x-7)
Step-by-step explanation:
The first 4 expressions can be factored with the difference of squares type of factoring.
For #5, the odd one out is (x+5)(x-7) because it isn't a factor of any of the standard form equations, while the others are
Answer:
type 2 in the first box,
13/4 in the second box, and
-9/8 in the third one
Step-by-step explanation:Notice that you are asked to write the following quadratic expression in vertex form, so you need to find the "x" value of the vertex, and then the "y" value of the vertex:
Which in our case is: -13/4
and the value of the y for the vertex is obtained using the functional expression when x equals -13/4:
Then your expression for this quadratic should be:
Then type 2 in the first box, 13/4 in the second box, and -9/8 in the third one
