Solution
Part A
The general form of the n-th term = a + (n-1)d
Here we are given the 8th term A8 = 28
, common difference (d) = 6
A8 = a + (n - 1) 6
28 = a + (8- 1)6
28 = a + 7*6
28 = a + 42
a = 28 - 42
a = -14
Part B
n-th term is 760. a = -14 and d = 6.
Plugging in the values in the general form, we get
760 = -14 + (n -1)6
760 = -14 + 6n - 6
760 = -20 + 6n
6n = 760 + 20
6n = 780
Dividing both sides by 6, we get
n = 780/6 = 130
The value of n is 130
Answer:
The distance from his starting point is <u>6.7 m</u>.
Step-by-step explanation:
Given:
Shane marched 3 m East and 6 m north.
Now, to get the distance from his starting point.
Let the distance from the starting point be
Now, to solve using pythagorean theorem:
<em>Using square root on both sides we get:</em>
<u>So, the distance from the starting point nearest to tenth is 6.7 m.</u>
Therefore, he is 6.7 m from his starting point.
Did you make a mistake because none of these ordered pairs are a solution.
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