Answer:
- <u><em>beta decay</em></u>
Explanation:
The <em>process</em> is represented by the nuclear equation:
→ 
Where:
- n represents a neutron,
- p represents a proton, and
- β represents an electron.
The superscripts to the leff of each symbol is the mass number (number of protons and neutrons), and the subscript to the left means the atomic number (number of protons).
Then, in this process a neutron is being transformed into a proton by the emssion of an electron (from inside the nucleus of the atom).
This electron is named beta (β) particle, and the process is called <u><em>beta decay</em></u>, because the neutron is changing into other subatomic particles.
Answer:
B
Explanation:
Asteroid - A rock that rvolves arounf the sun / star.
Moon - A natural satillite that revolves around earth/ planet.
Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.
Explanation:
Conversion of degree Celsius to Kelvin :
K=^oC+273
Conversion of degree Celsius to degrees Fahrenheit :
^oF=(\frac{9}{5}\times ^oC)+32
By using these two conversion factors, we get the three temperature readings all mean the same thing.
For option A :
K=^oC+273=100+273=373K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF
For option B :
K=^oC+273=100+273=373K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF
For option C :
K=^oC+273=0+273=273K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF
For option D :
K=^oC+273=0+273=273K
^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF
From the given options, only option (D) is correct.
Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit
Hope this helps!
P1T2 = P2T1
(3.8)(36)=25P2
136.8=25P2
136.8/25=P2
P2=5.472atm
Answer:
The charged carbon atom of a carbocation has a complete octet of valence shell electrons
Explanation:
A charged carbon atom of a carbocation has a valence shell that is not filled, <u>that's why it acts as an electrophile (or a Lewis base)</u>. This unfilled valence shell is also the reason of the nucleophilic attack that takes place during the second step of a SN1 reaction.
