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Harrizon [31]
3 years ago
13

What is chemistry the study of?

Chemistry
2 answers:
IRINA_888 [86]3 years ago
8 0
Chemistry is the study of substances—that is, elements and compounds.
amid [387]3 years ago
8 0

Chemistry is the study of substances—that is, elements and compounds.

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Please help with the equation in picture
matrenka [14]
Maybe 47.999 g if I can’t I’m sorry.
5 0
3 years ago
an alien civilization has different names and symbols for six elements. place each element in the correct location in the period
Rina8888 [55]

Answer:

All you have to do is count the number of electrons in the shells and place them according to the atomic number. I just did it.

Explanation:

7 0
3 years ago
Consider the following reaction at 298.15 K: Co(s)+Fe2+(aq,1.47 M)⟶Co2+(aq,0.33 M)+Fe(s) If the standard reduction potential for
fgiga [73]

Answer:

The correct answer is 0.186 V

Explanation:

The two hemirreactions are:

Reduction: Fe²⁺ + 2 e- → Fe(s)  

Oxidation : Co(s)  → Co²⁺ + 2 e-

Thus, we calculate the standard cell potential (Eº) from the difference between the reduction potentials of cobalt and iron, respectively,  as follows:

Eº = Eº(Fe²⁺/Fe(s)) - Eº(Co²⁺/Co(s)) = -0.28 V - (-0.447 V) = 0.167 V

Then, we use the Nernst equation to calculate the cell potential (E) at 298.15 K:

E= Eº - (0.0592 V/n) x log Q

Where:

n: number of electrons that are transferred in the reaction. In this case, n= 2.

Q: ratio between the concentrations of products over reactants, calculated as follows:

Q = \frac{ [Co^{2+} ]}{[Fe^{2+} ]} = \frac{0.33 M}{1.47 M} = 0.2244

Finally, we introduce Eº= 0.167 V, n= 2, Q=0.2244, to obtain E:

E= 0.167 V - (0.0592 V/2) x log (0.2244) = 0.186 V

4 0
4 years ago
Which of these solutes raises the boiling point of water the most?
Murljashka [212]

Answer:

D. ionic sodium phosphate (Na3PO4)

Explanation:

8 0
3 years ago
The label on a bottle of medicine reads​ "Each 5 mL teaspoonful contains​ glucose, 1.87​ g; levulose, 1.87​ g; and phosphoric​ a
Alexandra [31]

(a) 43.6 mg; (b) 520 mg

(a) <em>Mass of phosphoric acid (PA) in a dose </em>

Mass of PA = 2 tsp × (21.8 mg PA/1 tsp) = 43.6 mg PA

(b) <em>Mass of PA in the bottle </em>

<em>Step 1</em>. Convert <em>ounces to millilitres </em>

Volume = 4 oz × (30 mL/1 oz) = 120 mL

<em>Step 2.</em> Calculate the mass of PA

Mass of PA = 120 mL × (21.8 mg PA/5 mL) ≈ 520 mg PA

4 0
4 years ago
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