Triangles ABC and DEF may or may not be congruent, because the angle-angle-angle (AAA) postulate is not a criterion for congruency of any two triangles. This is because the angle-angle-angle postulate only incorporates the angles of the triangles, and the side lengths are not specified, so congruency may or may not be true for these triangles.
Answer:
f (3) is equal to 31
Step-by-step explanation:
f (3) means that x is equal to 3 [hence f (x) ---> f (3)]
Plugin 3 into all the x values to solve:
4(3)^2 - 2(3) + 1
4(9) - 6 + 1
36 - 6 + 1
30 + 1
31
f (3) is equal to 31
Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
A=(2,4); B=(3,9); C=(4,1)
A'=(4,-2); B'=(9,-3); C'=(1,-4)
All the points P=(x,y) change to P'=(y,-x), this corresponds to a rotation counterclockwise about the origin, then:
Answer: Triangle ABC is
First box: rotated counterclockwise
Second box: 90° about the origin
to form triangle A'B'C'
The question doesn’t make sense.
