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3 years ago

Please do it fast......

Mathematics

1 answer:

quester [9]3 years ago

5 0

For the first term, 15 you must subtract 12 to get to the second term, whereas for the second term in the original ratio, you must subtract 14 to get to the second number, 4.

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Goat on a Rope

mariarad [96]

Answer:

the area of grass is 314 square feet

Step-by-step explanation:

The radius of the circle the goat can reach is given by the length of the rope that ties the goat to the post (10 ft)

Then the area of the circle is: $Area=\pi\,R^2=3.14\,(10\,\,ft)^2=3.14 * (100)\,ft^2=314 \,\,ft^2$

So the area of grass is 314 square feet

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3 years ago

A cable hangs between two poles of equal height and 34 feet apart. At a point on the ground directly under the cable and x feet

Sergio039 [100]

Answer:

5000

Step-by-step explanation:

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3 years ago

Please help, I am extremely bad at graphing.

exis [7]

The correct answer is c

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3 years ago

For the following equations, find:

astraxan [27]

Answer:

to be honest with you, i dont know for sure,but I can tell that this is a really hard question, and for once I cant help someone, I am so sorry about that, but I will try to find the answer so that I can help you if you would like me to

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2 years ago

A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sa

ziro4ka [17]

Answer:

The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.

Step-by-step explanation:

We have a probability of making an individual sale of p=0.15.

We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:

$P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}$

As we see in the equation, n has to be equal or big than 4.

In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.

This probability can be calculated adding the probability from n=4 to n=6:

$P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008$

5 0

3 years ago