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Tcecarenko [31]
3 years ago
15

Write a pair of integers whose sum is- -8

Mathematics
1 answer:
Vlad [161]3 years ago
6 0

Answer:

-3+(-5)

Checking our answer:

Adding this does indeed give -8

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In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
Angle a and b are supplementary angles. If m a = (x – 40)0 and m b = (x + 20)0, find the value of x, m a and m b
serious [3.7K]

Answer:

∠ a = 60° , ∠ b = 120°

Step-by-step explanation:

Supplementary angles sum to 180° then

x - 40 + x + 20 = 180 , that is

2x - 20 = 180 ( add 20 to both sides )

2x = 200 ( divide both sides by 2 )

x = 100

Then

∠ a = x - 40 = 100 - 40 = 60°

∠ b = x + 20 = 100 + 20 = 120°

5 0
2 years ago
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