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Anon25 [30]
3 years ago
12

Question 3, help please!

Mathematics
1 answer:
White raven [17]3 years ago
4 0

The answer is not defined.

Explanation:

The given matrix is $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$

The matrix $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$ has dimensions 2\times 2

This means that the matrix has 2 rows and 2 columns.

Also, the matrix $\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$ has dimensions 2\times1

This means that the matrix has 2 rows and 1 column.

Since, the matrices can be added only if they have the same dimensions.

In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.

Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.

Hence, the addition of these two matrices is not defined.

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The length of ZX is 2 units. What is the perimeter of triangle XYZ?
dezoksy [38]

Keywords

triangle,perimeter,distance, length, side, points

we know that

The <u>perimeter</u> of a<u> triangle</u> is the sum of the three <u>length</u> <u>side</u>

To find the<u> length</u> <u>side</u> calculate the <u>distance</u> between two <u>points</u>

The formula to calculate the <u>distance</u> between to <u>points</u> is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}


Step 1

Find the <u>distance</u> ZY

Z(1,0)\\Y(3,1)  

substitute the values


d=\sqrt{(1-0)^{2}+(3-1)^{2}}


dZY=\sqrt{5}\ units


Step 2

Find the <u>distance</u> XY

X(-1,4)\\Y(3,1)  

substitute the values


d=\sqrt{(1-4)^{2}+(3+1)^{2}}


dXY=\sqrt{25}=5\ units  

Step 3

Find the <u>perimeter</u> of the <u>triangle</u>

P=ZX+ZY+XY

we have

dZX=2\sqrt{5}\ units


dZY=\sqrt{5}\ units


dXY=5\ units  

Substitute

P=(2\sqrt{5}+\sqrt{5}+5)\ units

therefore

the answer is

P=(3\sqrt{5}+5)\ units

4 0
3 years ago
Read 2 more answers
Solve -np-80&lt;60 for n. Show your work.<br><br> Solve 2a-5d=30 for d. Show your work.
xz_007 [3.2K]

-np-80 < 60\qquad\text{change the signs}\\\\np+80

------------------------------------------------------

2a-5d=30\qquad\text{subtract 2a from both sides}\\\\-5d=-2a+30\qquad\text{change the signs}\\\\5d=2a-30\qquad\text{divide both sides by 5}\\\\d=0.4a-6

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3 years ago
How can you use the quadratic formula to complete a square?
Marina86 [1]
It has become somewhat fashionable to have students derive the Quadratic Formula themselves; this is done by completing the square for the generic quadratic equation ax2 + bx + c = 0. While I can understand the impulse (showing students how the Formula was invented, and thereby providing a concrete example of the usefulness of abstract symbolic manipulation), the computations involved are often a bit beyond the average student at this point.
6 0
3 years ago
Read 2 more answers
The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

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2 years ago
2. ART An artist created a statue in the shape of a
son4ous [18]

Answer is in the photo. I can't attach it here, but I uploaded it to a file hosting. link below! Good Luck!

tinyurl.com/wpazsebu

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3 years ago
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