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Blababa [14]
3 years ago
15

2. A highway makes an angle of 6 with the horizontal. This angle is maintained for a horizontal distance of 5 miles. To the near

est hundredth of a mile, how high does the highway rise in this 5-mile section? Show the steps you use to find the distance.
Mathematics
1 answer:
hoa [83]3 years ago
7 0
Given:
angle of 6 : i'm assuming this is 6 degrees.
distance of 5 miles.

tan(6) = rise/5 mi
rise = 5 mi * tan(6)
rise = 5 mi * 0.10510423526
rise = 0.52552117632

rise = 0.53 miles.
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2 years ago
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inn [45]

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3 years ago
Solve ABC <br>c=10, B=35°, C=65%​
NISA [10]

Answer:

Part 1) The measure of angle A is A=80\°

Part 2) The length side of a is equal to a=10.9\ units

Part 3) The length side of b is equal to b=6.3\ units

Step-by-step explanation:

step 1

Find the measure of angle A

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

A+35\°+65\°=180\°

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A=180\°-100\°=80\°

step 2

Find the length of side a

Applying the law of sines

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}

a=\frac{10}{sin(65\°)}(sin(80\°))

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step 3

Find the length of side b

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

substitute the given values

\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}

b=\frac{10}{sin(65\°)}(sin(35\°))

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lidiya [134]
.07×1.22 = ?
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answer= 0.0854
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3 years ago
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