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Irina-Kira [14]
3 years ago
6

Tim throws darts at a dartboard that has numbers one through 20 in a bull’s-eye in the middle. 10 throws a dart 50 times, and he

hits the bull’s-eye 10 times. What is the experimental probability that Tim hits the bull’s-eye? Tim throws darts at a dartboard that has numbers one through 20 and a bull’s-eye in the middle. Tim throws a dart 50 times, and he hits the bull’s-eye 10 times. What is experimental probability that 10 hits the bull’s-eye?
A.) 1/50

B.) 1/10

C.) 1/2

D.) 1/5
Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Answer:

D.) 1/5

Explanation:

Experimental probability is the ratio of the number of successes to the number of trials.

In this case, success is a bulls-eye.  Tim had 10 bulls-eyes.  The total number of trials  is 50.  This makes the experimental probability 10/50, or 1/5.

Westkost [7]3 years ago
6 0

Answer:

The answer is D. 1/5 Hopefully this helps!

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AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is 6 a b^{2}(a+2)(2 a-1)

<u>Solution:</u>

Given, expression is 12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

We have to factorize the given expression completely.

Now, take the expression

12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

Taking b^2 as common term,

b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)

Taking "a" as common term,

b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)

Taking "6" as common term,

b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)

Splitting "3a" as "4a - a" we get,

b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)

\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}

Hence, the factored form of given expression is 6 a b^{2}(a+2)(2 a-1)

4 0
3 years ago
Which statement is true about the equations 3x + 4y = 12 and ¿-X- = = 1?
jarptica [38.1K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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6 0
2 years ago
B. At the circus, three adult tickets and five child tickets cost $51, and five adult tickets
allsm [11]

Answer: x = $7, y = $6

Step-by-step explanation:

Let x be the cost of an adult ticket

Let y be the cost of a children's ticket

Translate these sentences to algebra:

At the circus, three adult tickets and five child tickets cost $51: 3x + 5y = 51

Five adult tickets and two child tickets cost $47: 5x + 2y = 47

Now we have two equations. Let's use substitution to solve.

3x + 5y = 51

3x = 51 - 5y

.: x = 17 - 5y/3

Now substitute this value of x into the second equation to find the numerical value of y:

5(17 - 5y/3) + 2y = 47

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Now find x:

x = 17 - 5y/3

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.: x = 7

So an adult ticket costs $7, and a child ticket costs $6 :)

3 0
2 years ago
Dakota and Christine went shopping. Dakota bought two scarves and one hat for $13 Christine bought one scarves and two hats for
White raven [17]
One scarf=s
One hat=h

2s+h=13
s+2h=14

h=13-2s
(plug that into the other equation)

s+2(13-2s)=14
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26-3s=14
-3s=-12
s=4

One hat=$5
One scarf=$4
5+4=9
Price of one hat AND one scarf is $9
5 0
2 years ago
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