John dana and douglas painted a room
they have combined effort so
john+dana+douglas=total room
total room=100%=1/1=1
so 1 whole=8/8 so
2/8 is painted by john so they don't need to paint that so
so
2/8+dana+douglas=8/8
subtract 2/8 frm both sides
dana+dogluas=(8-2)/8=6/8
dana+douglas=6/8
dana painted same as douglas so divide by 2
dana=douglas=3/8
so A is 6/8 or 3/4
B is 2/8+3/8+3/8=8/8 or 2/8+dana+douglas=8/8
Answer:
x=64
Step-by-step explanation:
Both the semicircle that says 180, and the right angle sign in the image serve to support the idea that all parts of the figure equal 90
Therefore, it is safe to say that you need to subtract 26 from 90 in order to solve for x.
90-26 = 64
Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Answer:
.9 or 90%
.1 or 10%
Step-by-step explanation:
E= Exam
P=Paper
E= .71
P= .45
E∩P=.26
A.) E∪P=?
E∪P= E+P-E∩P
.71+.45-.26= .9
B.) E'∩P' = (E∪P)'
(E∪P)' = 1-.9 = .1
