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4 years ago

11

What bag is heavier 2 kilograms or 3000grams

2 answers:

Alina [70]4 years ago

8 0

3000 grams because 2 kilograms is the same as 2000 grams.

3000>2000

pav-90 [236]4 years ago

3 0

3000 grams because 2 kilograms is 2000 grams and 3000 is greater than 2000

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Find the seventh term of the

jekas [21]

Answer:

$T_7 = \frac{64}{729}$

Step-by-step explanation:

Given

$a =1$

$r = \frac{2}{3}$

Required

Determine the 7th term

The nth term of a gp is:

$T_n = a * r^{n-1$

So, we have:

$T_7 = 1 * \frac{2}{3}^{7-1$

$T_7 = 1 * \frac{2}{3}^{6$

$T_7 = 1 * \frac{2^6}{3^6}$

$T_7 = 1 * \frac{64}{729}$

$T_7 = \frac{64}{729}$

6 0

3 years ago

Oh freight elevator can hold a maximum weight of 3500 pounds and delivery man weighs 200 pounds is delivering curtains that each

mario62 [17]

Answer:

$200+48n\leq 3500$

$n\leq 66.7$

Step-by-step explanation:

The freight elevator can hold a maximum weight of 3500 pounds
The delivery man weighs 200 pounds
Each carton weighs 48 pounds

Let the number of cartons he can safely put on the elevator at one time=n

Total weight of Carton=48n

Since the weight of the man and the cartons combined must not be more than 3500 pounds,

Therefore,an inequality that represents the situation is:

$200+48n\leq 3500$

We can solve for n if required

$200-200+48n\leq 3500-200\\48n\leq 3200\\\text{Divide both sides by 48}\\n\leq66.7$

The delivery man can safely carry 66 Cartons.

4 0

3 years ago

What are the equations of the asymptotes of the graph of f(x)=(5/x+7)−8 ?

ludmilkaskok [199]

Answer:

$\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1$

The graph of the function is also attached.

Step-by-step explanation:

Considering the expression

$\:f\left(x\right)=\left(\frac{5}{x}+7\right)-8\:\:$

$\mathrm{Simplify}\:\frac{5}{x}+7-8:\quad \frac{5}{x}-1$

$\mathrm{Vertical\:asymptotes\:of\:}\frac{5}{x}-1:$

Go over every undefined point x = a and check if at least one of the following statement is true.

$\lim _{x\to a^-}f\left(x\right)=\pm \infty$

$\lim _{x\to a^+}f\left(x\right)=\pm \infty$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{5}{x}-1\mathrm{\:and\:compare\:to\:zero}$

$x=0$

The following points are undefined

$x=0$

$\mathrm{The\:vertical\:asymptotes\:are:}$

$x=0$

$\mathrm{Horizontal\:Asymptotes\:of\:}\frac{5}{x}-1:$

$\mathrm{Check\:if\:at\:}x\to \pm \infty \mathrm{\:the\:function\:}y=\frac{5}{x}-1\mathrm{\:behaves\:as\:a\:line,\:}y=mx+b$

$\mathrm{Find\:an\:asymptote\:for\:}x\to -\infty \::$

$\lim _{x\to -\infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to -\infty \:}\frac{\frac{5}{x}-1}{x}=0$

$\lim _{x\to -\infty \:}f\left(x\right)-mx=\lim _{x\to -\infty \:}\frac{5}{x}-1-0x=-1$

$y=-1$

$\mathrm{Find\:an\:asymptote\:for\:}x\to \infty:$

$\lim _{x\to \infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to \infty \:}\frac{\frac{5}{x}-1}{x}=0$

$\lim _{x\to \infty \:}f\left(x\right)-mx=\lim _{x\to \infty \:}\frac{5}{x}-1-0x=-1$

$y=-1$

$\mathrm{The\:horizontal\:asymptote\:is:}$

$y=-1$

Therefore,

$\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1$

The graph of the function is also attached.

6 0

4 years ago

Read 2 more answers

Its math and its really hard

Juliette [100K]

Answer:

Yes math is hard.

Step-by-step explanation:

Math includes a bunch of equations and mumbo-jumbo.

3 0

3 years ago

In a sale, a clothes shop reduces its 15%.

polet [3.4K]

The new cost would be 19.55.

Explanation: 1. 23 * 0.15 = 3.45
2. 23 - 3.45= 19.55

8 0

3 years ago