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olganol [36]
3 years ago
12

If x – 10 is a factor of x2 - 8x - 20. what is the other factor?

Mathematics
2 answers:
viva [34]3 years ago
6 0

Answer:

<u>The other factor is (x+2)</u>

Step-by-step explanation:

x²- 8x - 20 =  (x + 2)(x - 10)

let me know if you need any other help:)

jekas [21]3 years ago
3 0

Answer:

(x+2)

Step-by-step explanation:

Our expression must be multiplied by another factor to make the needed equation, so lets multiply our factor by another factor where we use \alpha as a variable of the factor we don't know. We can now expand this and compare coefficients to try to determine our value for \alpha.

(x-10)(x+\alpha)=x^2-8x-20\\x^2-(10+\alpha)x-10\alpha=x^2-8x-20

The terms of the coefficients for each expression must be the same, so we can say that

-10-\alpha =-8

and

-10\alpha = -20

Solving both equations give us the same result,  

\alpha = 2

So we can use this to create a factor.

(x+2)(x-10)

what does this expand to give us?

x^2-8x-20

this is correct!

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Step-by-step explanation:

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"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

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well, we can check by simply getting the distance from the center to the point (4,-1).

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Hey there!

#1 ⬇️

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#2 ⬇️

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Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

6 0
3 years ago
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