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Vadim26 [7]
3 years ago
15

Rijndael, AES, CCMP are same as well as different. They are same in terms of how encryption is done and different in terms of wh

ether each one is a protocol, algorithm or a standard.CCMP is both, a protocol and a standard, Rijndael is:_________ a) standard only b) an algorithm c) a communications protocol. d) patented by US Government
Computers and Technology
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

Option (b) is the correct answer to this question.

Explanation:

AES is based on Rijndael Algorithm.

The Rijndael algorithm enables a choice of block sizes and key sizes. The choices are for each of 128, 192, or 256 bits. Once NIST implemented Rijndael for AES, it only specified one block size,128 bits, but maintained three major lengths of selection. IEEE 802.11I go a step and further limits when both the main size and length of the block for 128 bits. It simplifies deployment and relieves users during development from having to make yet again another decision.

Other options are incorrect because they are not related to the given scenario.

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What is the f(n) runtime of the following pseudocode: sum-0 for A = N/2 downto 1 for B-1 t increment sum by B Explain: exactly w
Romashka [77]

The diagram part of the question is incomplete but the mathematical part has been solved below for you . However when the diagram will be attached it will be answered too.

Answer:

Following is the solution for the Time complexity/ Run Time:

Given that:

A = N/2 to 1

B = 1 to 4N

By summation:

Time Complexity = Lower bound of A * Upper Bound of B

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By simplifying:

Time Complexity = N * 2N

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i hope it will help you!

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Explanation:

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Using the knowledge in computational language in python it is possible to write a code that smallest possible array that consists of only powers of two.

<h3>Writting the code in python:</h3>

<em>"public class GoodArray {"</em>

<em />

<em> "public static List<Integer> getQueryResults(long N, List<List<Integer>> queries) {"</em>

<em />

<em>  "List<Integer> res = new ArrayList<>();"</em>

<em>  int[][] arr = new int[queries.size()][3];</em>

<em>  "List<Integer> goodArray = new ArrayList<>();"</em>

<em>  "for (int i = 1; i <= N; i++) {"</em>

<em>   "int num = i;"</em>

<em>   "while (num % 2 == 0) {"</em>

<em>    "goodArray.add(num);"</em>

<em>    "num = num / 2;"</em>

<em>   }</em>

<em>  }</em>

<em>  int index = 0;</em>

<em>  for (List<Integer> l : queries) {</em>

<em>   arr[index][0] = l.get(0);</em>

<em>   arr[index][1] = l.get(1);</em>

<em>   arr[index][2] = l.get(2);</em>

<em>   index++;</em>

<em>  }</em>

<em>  Collections.sort(goodArray);</em>

<em>  "for (int i = 0; i < arr.length; i++) {"</em>

<em>   "int[] query = arr[i];"</em>

<em>   int l = query[0];</em>

<em>   int r = query[1];</em>

<em>   int m = query[2];</em>

<em>   int prod = 1;</em>

<em>   "for (int j = l - 1; j <= r - 1; j++) {"</em>

<em>    "prod = (int) (prod * goodArray.get(j)) % m;"</em>

<em>   }</em>

<em>   res.add(prod);</em>

<em>  }</em>

<em>  return res;</em>

<em> }</em>

<em />

<em>}</em>

See more about python at brainly.com/question/18502436

#SPJ1

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