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3 years ago

What is the answer of two plus two

Mathematics

2 answers:

lbvjy [14]3 years ago

7 0

Answer:

4 Because that’s what you get when you add them together

FinnZ [79.3K]3 years ago

4 0

Answer:

Two

Step-by-step explanation:

If you have one and added one you have two

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if the ratio of home fans to visiting fans is 5:2 and all 42000 seats in a stadium are filled, how many visiting fans are in att

jeka94

Answer:

12000

Step-by-step explanation:

Sum the parts of the ratio, 5 + 2 = 7

Divide the total seats by 7 to find the value of one part of the ratio

42000 ÷ 7 = 6000 ← value of 1 part of the ratio

visiting fans = 2 × 6000 = 12000

8 0

3 years ago

A container holds 0.7 liters of oil and vinegar 3/4 of that is vinegar how much oil is in the container

fgiga [73]

Answer:

There are 21/40 L or 0.525 L of vinegar in the container.

Step-by-step explanation:

3 0

3 years ago

65= t - 5 - 7 what is t

Nookie1986 [14]

Answer: t = 77

Step-by-step explanation:

To solve for t, we will simplify and isolate the variable.

Given:

65 = t - 5 - 7

Combine like terms:

65 = t - 12

Add 12 to both sides of the equation:

77 = t

7 0

2 years ago

Read 2 more answers

How can i prove this property to be true for all values of n, using mathematical induction.

chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

$\implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6}$

$\implies{ \frac{1(2)(3)}{6} }$

$\implies{ 1}$

Therefore, it is true for the first part.

In the second part we will assume that,

$\: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }$

and we will prove that,

$\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}$

$\: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}$

Henceforth, by using the principle of mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n.

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8 0

1 year ago

Tell which equation you would use to isolate a variable in order to solve the system using substitution. Explain your reasoning.

vampirchik [111]

2x+y=-10
Multiply both side by 3
2x*3+y*3=-10*3
6x+3y=-30

3x-y=0
Multiply both side by 2
3x*2-y*2=0*2
6x-2y=0
Next, use substitute property
6x+3y=-30
-
6x-2y=0
=
y=-30
3x-y=0
Substitute y with -30
3x-30=0
Add 30 to each side
3x-30+30=0+30
3x=30
Divided both side by 3
3x/3=30/3
x=10, so the solution pair is (10,-30). In this case, there is the first way to solve these two equation.
Then, I would use equation 3x+1.5y=-15 in this question by multiply 2x+y=-10 by multiplying both side by 3/2 to eliminate x and to solve variables for y. Hope it help!

3 0

3 years ago