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jolli1 [7]
3 years ago
12

What is 324,120,800 in scientific notation​

Mathematics
1 answer:
Maru [420]3 years ago
4 0
3.241208 × 10 to the eighth power
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L. - (6x - 5) = -6x +13​
zzz [600]

Answer:

No Solution.

Step-by-step explanation:

-(6x-5)=-6x+13

-6x+5=-6x+13

-6x-(-6x)+5=13

-6x+6x+5=13

0+5=13

5=13

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3 years ago
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3) You have a giant, giant hot tub. The hot tub just so happens to be a perfect cylinder. You cannot fill it
Nikitich [7]

Answer:

Probably 8!

Step-by-step explanation:

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I'm very confused on how to even figure out the question and what I'm supposed to do
Tasya [4]

Answer:

To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations. I hope this helped!

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2 years ago
2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
Oksana_A [137]

Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

$ COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0
3 years ago
M is the midpoint of CF for the points c(3,7) and f(5,5). Find MF
Marizza181 [45]
(4,6), Using the midpoint formula which is (( x1 + x2)/2), ((y1+y2)/2)
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